#include <bits/stdc++.h>
using namesapce std;
const int N=1e2+10;
const int INF=0x3f3f3f3f;
int n,a[N][N]; 
int main()
{
	cin<<n; 
	for(int i=1;i<=n;i++)
	{
		for(int j=1;j<=n;j++)
		{
			a[i][j]+=n-(n-i);
			cout<<a[i][j]<<" ";
			a[i][j+1]+=n*j;
		}
		cout<<endl;
	}
return o;
}

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