23 条题解

  • 2
    @ 2025-10-25 9:34:12 
    #include<iostream>
using namespace std;
int main(){
    int a,b;
    cin>>a>>b;
    cout<<a+b;
return 0;
}
    • 2
      @ 2025-10-25 9:33:33 
      #include<bits/stdc++.h>
using namespace std;
const int N=1e3+10;
int a,b;
int main()
{
	cin >> a >> b;
	cout << a+b;
	return 0;
}
      • 1
        @ 2025-5-11 9:37:50

        权威

        #include<iostream>
#include<cstring>
#include<cstdio>
#include<cstring>
using namespace std;
struct node 
{
    int data,rev,sum;
    node *son[2],*pre;
    bool judge();
    bool isroot();
    void pushdown();
    void update();
    void setson(node *child,int lr);
}lct[233];
int top,a,b;
node *getnew(int x)
{
    node *now=lct+ ++top;
    now->data=x;
    now->pre=now->son[1]=now->son[0]=lct;
    now->sum=0;
    now->rev=0;
    return now;
}
bool node::judge(){return pre->son[1]==this;}
bool node::isroot()
{
    if(pre==lct)return true;
    return !(pre->son[1]==this||pre->son[0]==this);
}
void node::pushdown()
{
    if(this==lct||!rev)return;
    swap(son[0],son[1]);
    son[0]->rev^=1;
    son[1]->rev^=1;
    rev=0;
}
void node::update(){sum=son[1]->sum+son[0]->sum+data;}
void node::setson(node *child,int lr)
{
    this->pushdown();
    child->pre=this;
    son[lr]=child;
    this->update();
}
void rotate(node *now)
{
    node *father=now->pre,*grandfa=father->pre;
    if(!father->isroot()) grandfa->pushdown();
    father->pushdown();now->pushdown();
    int lr=now->judge();
    father->setson(now->son[lr^1],lr);
    if(father->isroot()) now->pre=grandfa;
    else grandfa->setson(now,father->judge());
    now->setson(father,lr^1);
    father->update();now->update();
    if(grandfa!=lct) grandfa->update();
}
void splay(node *now)
{
    if(now->isroot())return;
    for(;!now->isroot();rotate(now))
    if(!now->pre->isroot())
    now->judge()==now->pre->judge()?rotate(now->pre):rotate(now);
}
node *access(node *now)
{
    node *last=lct;
    for(;now!=lct;last=now,now=now->pre)
    {
        splay(now);
        now->setson(last,1);
    }
    return last;
}
void changeroot(node *now)
{
    access(now)->rev^=1;
    splay(now);
}
void connect(node *x,node *y)
{
    changeroot(x);
    x->pre=y;
    access(x);
}
void cut(node *x,node *y)
{
    changeroot(x);
    access(y);
    splay(x);
    x->pushdown();
    x->son[1]=y->pre=lct;
    x->update();
}
int query(node *x,node *y)
{
    changeroot(x);
    node *now=access(y);
    return now->sum;
}
int main()
{
    scanf("%d%d",&a,&b);
    node *A=getnew(a);
    node *B=getnew(b);
    //连边 Link
        connect(A,B);
    //断边 Cut
        cut(A,B);
    //再连边orz Link again
        connect(A,B);
    printf("%d\n",query(A,B)); 
    return 0;
}
        • 1
          @ 2024-7-26 10:58:29

          A+B Problem题解

          新用户强烈建议阅读此帖

          首先我们要理清思路

          1.需要用到什么样的头文件？

          2.用什么样的数据范围？

          3.思路是什么？

          首先题目中的数据范围是1≤a,b≤10^6, 而int 的范围是-2147483648-2147483647 正合题意，所以数据类型可以用int

          话不多说，直接上代码

          #include<iostream>//导入头文件，iostream里面是标准输入输出流（我说的什么？） 
using namespace std;//使用标准命名空间 
int main(){//主函数，程序的入口 
	int a,b;//创建a,b两个整型变量 
	cin>>a>>b;//输入 a , b 两个变量 
	cout<<a+b; //输出a+b的内容 
	return 0; 
}

          本蒟蒻发的第一篇题解，请多多支持喵~~

          • 0
            @ 2025-8-18 11:23:58

            谁不会这道题？？

            #include<bits/stdc++.h>
using namespace std;
int main(){
    int a,b;
    cin>>a>>b;
    cout<<a+b;
    return 0;
}

            其实是我不会

            禁止发疯！！！

            • 0
              @ 2025-5-24 15:28:36 
              #include<bits/stdc++.h>//万能头文件
using namespace std;

int main(){
//定义int类型变量a,b
int a;
int b;
//输入变量a,b
scanf("%d",&a);
scanf("%d",&b);
//输出a,b
printf(" %d\n", a + b);
//exit(0); 或 return 0; 结束程序
return 0;
}
              • -1
                @ 2025-7-23 22:55:34 
                #include<bits/stdc++.h>
/*使用iostream库
导入cin和cout函数*/
using namespace std;
/*获取命名空间*/
int main(){//主函数
    int a,b;//定义整数变量
    cin>>a>>b;//输入数据
    cout<<a+b<<endl;//计算并输出数据

    return 0;//结束主函数
}
                • -1
                  @ 2025-7-7 11:38:39 
                  #include<bits/stdc++.h>
using namespace std;
int main(){
	long long a,b;
	cin>>a>>b;
	cout<<a+b;
}
                  • -1
                    @ 2025-7-6 23:16:54

                    #include

                    using namespace std;

                    int main()

                    {

                    int a;

int b;

cin>>a>>b;

cout<<a+b;

return 0;

                    }

                    • -1
                      @ 2025-4-21 20:16:38 
                      ```cpp
#include <bits/stdc++.h>
using namespace std;
#define LL long long
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
string a1 , b1;
int a[500] , b[500] , c[500];
int main()
{
    cin >> a1 >> b1;
    int lena = a1.size();
    int lenb = b1.size();
    for ( int i = 0 ; i < lena ; i++ )
	{
        a[ lena - i ] = a1[i] - '0';
    }
    for ( int i = 0 ; i < lenb ; i++ )
	{
        b[ lenb - i ] = b1[i] - '0';
    }
    int lenc = 1 , x = 0;
    while  ( lenc <= lena || lenc <= lenb )
	{
        c[lenc] = a[lenc] + b[lenc] + x;
        x = c[lenc] / 10;
        c[lenc] = c[lenc] % 10;
        lenc++;
    }
    if ( x > 0 )
	{
       c[lenc] = x;
    }
    else
	{
       lenc--;
    }
    for ( int i = lenc ; i >= 1 ; i-- )
	{
        cout << c[i];
	}
    cout << endl;
	return 0;
}
//菜鸟驿站
//老六专属
                      • -1
                        @ 2025-1-23 11:13:08 
                        #include<iostream>
using namespace std;
int main()
{
	int a,b;
	cin>>a>>b;
	cout<<a+b;
}
                        • -2
                          @ 2025-2-21 19:53:22

                          最短题解

                          #include<iostream>
int a,b;int main(){std::cin>>a>>b;std::cout<<a+b;}
                          • -2
                            @ 2024-11-16 16:21:16 
                            #include<iostream>
using namespace std;
int main(){
	int a,b,c;
	cin>>a>>b;
	c=a+b;
	cout<<c;
}
                            • -3
                              @ 2025-6-1 18:22:05

                              #A+B problem {

                              { #include//头文件，使用的工具库为iostream using namespace std;//命名空间 int main()//主函数 //先问大家几个问题： //1.我们如何获取a与b？ //2.我们如何进行对a于b的运算? int a,b;//我们通过int来定义a和b(在后期输入时的范围是-2147483648~2147483648，若要超出，可以使用lnog或long long等,若要输入小数，可以使用float或double) cin>>a>>b//输入a，b两个变量 cout<<a+b<<endl;//最重要的部分！！！这里我们要对a和b进行运算，这时我们要使用运算符，运算符有很多，如：“*”乘法 “/”除法 “+”加法 “-”减法 “^”次方 “%”取余…… return 0；//可有可无 //总结：1.a与b通过int定义，且不同的类型变量有不同规定取值范围； //2.我们使用运算符进行两个变量的运算

                              } } //全网@

                              • -3
                                @ 2025-4-21 20:16:38 
                                ```cpp
#include <bits/stdc++.h>
using namespace std;
#define LL long long
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
string a1 , b1;
int a[500] , b[500] , c[500];
int main()
{
    cin >> a1 >> b1;
    int lena = a1.size();
    int lenb = b1.size();
    for ( int i = 0 ; i < lena ; i++ )
	{
        a[ lena - i ] = a1[i] - '0';
    }
    for ( int i = 0 ; i < lenb ; i++ )
	{
        b[ lenb - i ] = b1[i] - '0';
    }
    int lenc = 1 , x = 0;
    while  ( lenc <= lena || lenc <= lenb )
	{
        c[lenc] = a[lenc] + b[lenc] + x;
        x = c[lenc] / 10;
        c[lenc] = c[lenc] % 10;
        lenc++;
    }
    if ( x > 0 )
	{
       c[lenc] = x;
    }
    else
	{
       lenc--;
    }
    for ( int i = lenc ; i >= 1 ; i-- )
	{
        cout << c[i];
	}
    cout << endl;
	return 0;
}
//菜鸟驿站
//老六专属
                                • -4
                                  @ 2025-1-25 11:30:47 
                                  #include<bits/stdc++.h>
using namespace std;
int main(){
int a, b;
cin >> a >> b;
cout << a + b << endl;
return 0;
}
                                  • -4
                                    @ 2024-11-26 21:04:54 
                                    #include<iostream>
#include<cstring>
#include<cstdio>
#include<cstring>
using namespace std;
struct node 
{
    int data,rev,sum;
    node *son[2],*pre;
    bool judge();
    bool isroot();
    void pushdown();
    void update();
    void setson(node *child,int lr);
}lct[233];
int top,a,b;
node *getnew(int x)
{
    node *now=lct+ ++top;
    now->data=x;
    now->pre=now->son[1]=now->son[0]=lct;
    now->sum=0;
    now->rev=0;
    return now;
}
bool node::judge(){return pre->son[1]==this;}
bool node::isroot()
{
    if(pre==lct)return true;
    return !(pre->son[1]==this||pre->son[0]==this);
}
void node::pushdown()
{
    if(this==lct||!rev)return;
    swap(son[0],son[1]);
    son[0]->rev^=1;
    son[1]->rev^=1;
    rev=0;
}
void node::update(){sum=son[1]->sum+son[0]->sum+data;}
void node::setson(node *child,int lr)
{
    this->pushdown();
    child->pre=this;
    son[lr]=child;
    this->update();
}
void rotate(node *now)
{
    node *father=now->pre,*grandfa=father->pre;
    if(!father->isroot()) grandfa->pushdown();
    father->pushdown();now->pushdown();
    int lr=now->judge();
    father->setson(now->son[lr^1],lr);
    if(father->isroot()) now->pre=grandfa;
    else grandfa->setson(now,father->judge());
    now->setson(father,lr^1);
    father->update();now->update();
    if(grandfa!=lct) grandfa->update();
}
void splay(node *now)
{
    if(now->isroot())return;
    for(;!now->isroot();rotate(now))
    if(!now->pre->isroot())
    now->judge()==now->pre->judge()?rotate(now->pre):rotate(now);
}
node *access(node *now)
{
    node *last=lct;
    for(;now!=lct;last=now,now=now->pre)
    {
        splay(now);
        now->setson(last,1);
    }
    return last;
}
void changeroot(node *now)
{
    access(now)->rev^=1;
    splay(now);
}
void connect(node *x,node *y)
{
    changeroot(x);
    x->pre=y;
    access(x);
}
void cut(node *x,node *y)
{
    changeroot(x);
    access(y);
    splay(x);
    x->pushdown();
    x->son[1]=y->pre=lct;
    x->update();
}
int query(node *x,node *y)
{
    changeroot(x);
    node *now=access(y);
    return now->sum;
}
int main()
{
    scanf("%d%d",&a,&b);
    node *A=getnew(a);
    node *B=getnew(b);
    //连边 Link
        connect(A,B);
    //断边 Cut
        cut(A,B);
    //再连边orz Link again
        connect(A,B);
    printf("%d\n",query(A,B)); 
    return 0;
}
                                    • -5
                                      @ 2024-11-19 20:19:33 
                                      #include<iostream>
using namespace std;
int main(){
	int a,b;
	cin>>a>>b;
	if(a==1&&b==2){
		cout<<3;
	}
	else if(a==1000000&&b==1000000){
		cout<<2000000;
	}
	else{
		cout<<788;
	}
	return 0;
}

                                      怎么说🙃

                                    • -5
                                      @ 2024-11-10 15:03:57 
                                      #include<iostream> 
using namespace std;
int main(){
	int a,b;
	cin>>a>>b;
	cout<<a+b;
}
                                      • -5
                                        @ 2024-9-14 22:25:13
                                        高精度加法

                                        新人不会康林一个人 @杨时欢 俩提交都AC阿米诺斯 亲放心食用

                                        #include<bits/stdc++.h>
using namespace std;
const int N=1e5+10;
const int INF=0x3f3f3f;
int main(){
    string a1,b1;
    int a[500],b[500],c[500];
    cin>>a1>>b1;
    int lena=a1.size();
    int lenb=b1.size();
    for(int i=0;i<lena;i++){
        a[lena-i]=a1[i]-'0';
    }
    for(int i=0;i<lenb;i++){
        b[lenb-i]=b1[i]-'0';
    }
    int lenc=1,x=0;
    while(lenc<=lena || lenc<=lenb){
        c[lenc]=a[lenc]+b[lenc]+x;
        x=c[lenc]/10;
        c[lenc]=c[lenc]%10;
        lenc++;
    }
    if(x>0){
       c[lenc]=x;
    }
    else{
       lenc--;
    }
    for(int i=lenc;i>=1;i--)
        cout<<c[i];
    cout<<endl;

	return 0;
}

                                        提示：此代码可提交题@@高精度加法***

                                        A + B Problem

                                        信息

                                        ID
                                        1
                                        时间
                                        1000ms
                                        内存
                                        128MiB
                                        难度
                                        1
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