14 条题解

  • 1
    @ 2026-3-23 20:54:14

    抄的 #include <bits/stdc++.h> using namespace std;

    int main() { char a[256]; int b; cin>>a>>b; char c[256]; int d=0; long long e=0; for(int i=0;a[i]!='\0';i++) { int g=a[i]-'0'; e=e*10+g; int h=e/b; e%=b; c[d++]=h+'0'; } c[d]='\0'; int i=0; while(c[i]'0') { i++; } if(id) { cout<<"0"; } else { for(;c[i]!='\0';i++) { cout<<c[i]; } } cout<<endl; return 0; }

    • 1
      @ 2025-3-26 22:08:37 
      #include<iostream> 
using namespace std;
string a;
int b;
const int N=1e6+532;
int a1[N],lena,c1[N],lenc,yu;
int main(){
	cin>>a>>b;
	lena=a.size();
	for(int i=0;i<lena;i++)a1[i] = a[i]-'0';
	for(int i=0;i<=lena;i++)
	{
		c1[i] = (yu*10+a1[i])/b;
		yu = (yu*10+a1[i])%b;
	}
	while(c1[lenc]==0&&lenc <lena-1)lenc++;
	for(int i=lenc;i<=lena-1;i++)cout<<c1[i];
	return 0;
}
      • 1
        @ 2024-12-6 18:45:25

        抄的😄

        #include<bits/stdc++.h>
using namespace std;
const int N=1e5+10;
long long x[N],c[N];
int main(){
	char a[10000]; 
	long long y;
	cin>>a>>y;
	int len1=strlen(a);
	for(int i=0;i<len1;i++){
		x[i]=a[i]-'0';
	}
	long long len=0;
	long long ans=0;
	for(int i=0;i<len1;i++){
		int f=0;
		ans=ans*10+x[i];
		if(ans>=y){
			f=ans/y;
			ans=ans%y;
		}
		c[len++]=f;
	}
	long long num=0;
	while(c[num]==0&&num<len){
		num++;
	}
	if(num>=len){
		cout<<"0";
		return 0;
	}
	for(int i=num;i<len;i++){
		cout<<c[i];
	}
	return 0;
}
      • 0
        @ 2021-11-13 20:52:41 
        /*****************************************
备注：
******************************************/
#include <queue>
#include <math.h>
#include <stack>
#include <stdio.h>
#include <iostream>
#include <vector>
#include <iomanip>
#include <string.h>
#include <algorithm>
using namespace std;
#define LL long long
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
int x[N];
int c[N];
int main()
{
	string a;
	LL y;
	cin >> a >> y;
	int lena = a.size();
	for(int i = 0 ; i < lena ; i++)
		x[i] = a[i] - '0';
	LL len = 0;
	LL ans = 0;
	for(int i = 0 ; i< lena ; i++)
	{
		int f = 0;
		ans = ans * 10 + x[i];
		if(ans >= y)
		{
			f = ans/y;
			ans = ans % y;
		}
		c[len++] = f;
	}
	LL num = 0;
	while(c[num] == 0 && num < len)
		num++;
	if(num >= len)
	{
		cout << "0";
		return 0;
	}
	for(int i = num ; i < len ; i++)
		cout << c[i];
	return 0;
}
        • @ 2023-1-25 22:41:17 
          ```
/*****************************************
备注：
******************************************/
#include <queue>
#include <math.h>
#include <stack>
#include <stdio.h>
#include <vector>
#include <iomanip>
#include <string.h>
#include <algorithm>
const int INF = 0x3f3f3f3f;
```
      • -1
        @ 2023-10-25 20:07:16

        #include #include <math.h> #include #include <stdio.h> #include #include #include #include <string.h> #include using namespace std; const int N=1e5+10; const int INF=0x3f3f3f3f; char a[N]; int a1[N],c1[N],lenc; int b,x; int main(){ cin>>a>>b; int lena=strlen(a);

        for(int i=0;i<lena;i++)
	a1[i]=a[lena-i-1]-'0';


for(int i=lena-1;i>=0;i--){
	c1[i]=(x*10+a1[i])/b;
	x=(x*10+a1[i])%b;
	
}

lenc=lena;
while(c1[lenc]==0&&lenc>0)
	lenc--;
for(int i=lenc;i>=0;i--)
	cout<<c1[i];



return 0;

        }

        • -1
          @ 2023-10-25 20:06:43

          #include<bits/stdc++.h> using namespace std; const int n=1e5+10; const int inf=0x3f3f3f3f;

          char a[n]; int la,lc,a1[n],c1[n],x,b; int main() { cin>>a>>b; la=strlen(a); for(int i=0;i<la;i++){ a1[i]=a[la-i-1]-'0'; }

          for(int i=la-1;i>=0;i--){
	c1[i]=(x*10+a1[i])/b;
	x=(x*10+a1[i])%b;
}
lc=la;
while(c1[lc]==0 && lc>0){
	lc--;
}
for(int i=lc;i>=0;i--){
	cout<<c1[i];
}
return 0;

          }

          • -2
            @ 2024-10-22 16:45:44 
            #include<iostream> 
using namespace std;
string a;
int b;
const int N=1e6+532;
int a1[N],lena,c1[N],lenc,yu;
int main(){
	cin>>a>>b;
	lena=a.size();
	for(int i=0;i<lena;i++)
	{
		a1[i] = a[i]-'0';
	}
	for(int i=0;i<=lena;i++)
	{
		c1[i] = (yu*10+a1[i])/b;
		yu = (yu*10+a1[i])%b;
	}
	while(c1[lenc]==0&&lenc <lena-1)
	{
		lenc++;
	}
	for(int i=lenc;i<=lena-1;i++)
	{
		cout<<c1[i];
	}
	return 0;
}
          • -2
            @ 2023-11-25 20:44:17

            #include #include <math.h> #include #include <stdio.h> #include #include #include #include <string.h> #include using namespace std; #define LL long long const int N = 1e6 + 10; const int INF = 0x3f3f3f3f; string a; int a1[N],c1[N],lena,lenc,yu; int main() { cin >> a>>b; lena = a.size(); for(int i = 0;i < lena;i++) { a1[i]=a[i]-'0'; } for(int i =0;i <lena;i++) { c1[i]=(yu *10+a1[i])/b; yu = (yu *10 + a1[i])%b; } while(c1[lenc] == 0&&lenc<lena - 1) { lenc++; } for(int i = lenc;i < lena;i++ { cout <<c1[i]; } return 0; }

            • -2
              @ 2023-11-25 20:44:00 
              #include<iostream>
#include<cstdio>
#include<cmath>
#include<algorithm>
#include<string>
#include<cstring>
const int INF=0x3f3f3f3f;
const int N=1e5+10;
using namespace std;
string a;
int b;
int a1[N],lena,c1[N],lenc,yu;
int main(){
	cin>>a>>b;
	lena=a.size();
	for(int i=0;i<lena;i++)
	{
		a1[i] = a[i]-'0';
	}
	for(int i=0;i<=lena;i++)
	{
		c1[i] = (yu*10+a1[i])/b;
		yu = (yu*10+a1[i])%b;
	}
	while(c1[lenc]==0&&lenc <lena-1)
	{
		lenc++;
	}
	for(int i=lenc;i<=lena-1;i++)
	{
		cout<<c1[i];
	}
	return 0;
}
              • -2
                @ 2023-10-29 20:26:16 
                #include <bits/stdc++.h>
using namespace std;
#define LL long long
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
int x[N];
int c[N];
int main()
{
	string a;
	LL y;
	cin >> a >> y;
	int lena = a.size();
	for(int i = 0 ; i < lena ; i++)
		x[i] = a[i] - '0';
	LL len = 0;
	LL ans = 0;
	for(int i = 0 ; i< lena ; i++)
	{
		int f = 0;
		ans = ans * 10 + x[i];
		if(ans >= y)
		{
			f = ans/y;
			ans = ans % y;
		}
		c[len++] = f;
	}
	LL num = 0;
	while(c[num] == 0 && num < len)
		num++;
	if(num >= len)
	{
		cout << "0";
		return 0;
	}
	for(int i = num ; i < len ; i++)
		cout << c[i];
	return 0;
}
              • -2
                @ 2023-10-25 20:15:20

                #include <math.h> #include #include <stdio.h> #include #include #include #include <string.h> #include #include<bits/stdc++.h> using namespace std; const int N = 1e5 + 10; const int INF = 0x3f3f3f3f; char a[N]; int lena,lenc,a1[N],c1[N],x,b; int main(){ cin >> a >> b; lena = strlen(a); for(int i = 0;i < lena;i++) a1[i] = a[lena - i - 1] - '0'; for(int i = lena - 1;i >= 0;i--) { c1[i] = (x * 10 + a1[i]) / b; x = (x * 10 + a1[i]) % b; } lenc = lena; while(c1[lenc] == 0 && lenc > 0) lenc--; for(int i = lenc;i >= 0;i--) cout << c1[i];

                return 0;

                }

                • -3
                  @ 2024-10-22 16:48:34

                  little bird ,little bird

                  #include<iostream> 
using namespace std;
string a;
int b;
const int N=1e6+532;
int a1[N],lena,c1[N],lenc,yu;
int main(){
	cin>>a>>b;
	lena=a.size();
	for(int i=0;i<lena;i++)
	{
		a1[i] = a[i]-'0';
	}
	for(int i=0;i<=lena;i++)
	{
		c1[i] = (yu*10+a1[i])/b;
		yu = (yu*10+a1[i])%b;
	}
	while(c1[lenc]==0&&lenc <lena-1)
	{
		lenc++;
	}
	for(int i=lenc;i<=lena-1;i++)
	{
		cout<<c1[i];
	}
	return 0;
}
小鸟专属
                • -3
                  @ 2023-4-30 11:22:19 
                  #include <math.h>
#include <stack>
#include <stdio.h>
#include <iostream>
#include <vector>
#include <iomanip>
#include <string.h>
#include <algorithm>
#include<bits/stdc++.h>
using namespace std;
int a[510],c[1010];
int la,b,x;
string s1,s2; 
int main(){
	cin >> s1 >> b;
	la=s1.size();
    for (int i=0; i<la; i++){
		a[i+1]=s1[i]-'0';
	}
	for (int i=1; i<=la; i++){
		c[i]=(x*10+a[i])/b;
		x=(x*10+a[i])%b;
	}
	

	int lc = 1;
	
	while(c[lc]==0&&lc<la)lc++;
	for (int i=lc; i<=la; i++)cout <<c[i]; 
	return 0;
}
                  • -4
                    @ 2023-1-26 12:38:02 
                    #include<bits/stdc++.h>
using namespace std;
int x[2005];
int c[2005];
int main()
{
  string a;
  long long y,ans=0,l=0;
  cin>>a>>y;
  int la=a.size(),b=0;
  for(int i=la-1; i>=0; i=i-1)x[la-i-1]=int(a[i]-'0');
  for(int i=la-1; i>=0; i=i-1)
  {
    ans=ans*10+x[i];
    c[la-i-1]=ans/y;
    ans=ans%y;
  }
  for(int i=0; i<la; i=i+1)
  {
    if(c[i]==0)l=l+1;
    else break;
  }
  for(int i=l; i<la; i=i+1)
  {
    if((c[i]!=0)||(i==la-1))b=1;
    if(b==1)printf("%d",c[i]);
  }
  if(l>=la-1)printf("0\n");
  return 0;
}
                    • 1

                    高精度除以低精

                    信息

                    ID
                    1189
                    时间
                    1000ms
                    内存
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                    难度
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