8 条题解

  • 1
    @ 2023-10-22 18:25:33
    #include <bits/stdc++.h> //liaohaoyu
    using namespace std;
    int s[1001][1001]; //本来想开114514的 
    int main()
    {
     
    
    	int n, m, k;
    	cin >> n >> m >> k;
    	for(int i = 1;i <= n;i++)
    	{
    		for(int j = 1;j <= m;j++)
    		{
    			cin >> s[i][j];
    			s[i][j] = s[i-1][j] + s[i][j-1] - s[i-1][j-1] + s[i][j];
    		}
    	}
    	for(int i = 1;i <= k;i++)
    	{
    		int x, x2, y, y2;
    		cin >> x >> y >> x2 >> y2;
    		cout << s[x2][y2] - s[x2][y-1] - s[x-1][y2] + s[x-1][y-1] << endl; 
    	}
    } 
    
    • 1
      @ 2023-4-30 14:46:43
      #include <math.h>
      #include <stack>
      #include <stdio.h>
      #include <iostream>
      #include <vector>
      #include <iomanip>
      #include <string.h>
      #include <algorithm>
      using namespace std;
      #define LL long long
      const int N = 1e6 + 10;
      const int INF = 0x3f3f3f3f;
      int n,m,k,a[1005][1005];
      int main(){
      	
      	cin >> n >> m >>k;
      	for (int i=1; i<=n; i++){
      		for (int j=1; j<=m; j++){
      			cin >> a[i][j];
      			a[i][j]=a[i-1][j]+a[i][j-1]-a[i-1][j-1]+a[i][j];
      		}
      	}
      	while(k--){
      		int y1,y2,x1,x2;
      		cin >> x1>>y1>>x2>>y2;
      		cout<<a[x2][y2]-a[x2][y1-1]-a[x1-1][y2]+a[x1-1][y1-1]<<" "<<endl;
      	}
      	return 0;
      }
      
      • 1
        @ 2023-3-12 15:48:29
        /*********************************
               all rights reserved.
        *********************************/
        #include<bits/stdc++.h>
        using namespace std;
        int n,m,f[1005][1005],k,x1,x2;
        int y3,y2,x;
        int main()
        {    
            cin>>n>>m>>k;
            for(int i=1;i<=n;i++) {
            	for(int j=1;j<=m;j++) {
            		cin>>x;
            		f[i][j]=x+f[i-1][j]+f[i][j-1]-f[i-1][j-1];
        		}
        	}
        	while(k--) {
        		cin>>x1>>y3>>x2>>y2;
        		cout<<f[x2][y2]-f[x1-1][y2]-f[x2][y3-1]+f[x1-1][y3-1]<<"\n";
        	}
            return 0;
        }
        
        • 1
          @ 2023-1-23 12:38:42
          #include<iostream> 
          using namespace std;
          int a[1005][1005];
          int main(){
          	int n,m,x;
          	cin>>n>>m>>x;
          	for(int i=1;i<=n;i++){
          		for(int j=1;j<=m;j++){
          			cin>>a[i][j];
          			a[i][j]=a[i-1][j]+a[i][j-1]-a[i-1][j-1]+a[i][j];
          		}
          	}
          	for(int i=1;i<=x;i++){
          		int x1,x2,y1,y2;
          		cin>>x1>>y1>>x2>>y2;
          		cout<<a[x2][y2]-a[x2][y1-1]-a[x1-1][y2]+a[x1-1][y1-1]<<"\n";
          	}
          }
          
          
          • 0
            @ 2024-7-24 11:26:40
            
            //#define int long long
            
            using namespace std;
            
            const int N = 1e3 +10;
            
            const int INF=0x3f3f3f;
            
            int n,m,z,sx,sy,ex,ey,a[N][N],b[N][N],d[N];
            
            int main(){
            
            cin>>n>>m>>z;    
                for(int i = 1;i<=n;i++){
                    for(int j = 1;j<=m;j++){
                        cin>>a[i][j];
                        a[i][j] = a[i-1][j] + a[i][j-1]  - a[i-1][j-1] + a[i][j];
                    }
                }
                for(int i = 1;i<=z;i++){
                    cin>>sx>>sy>>ex>>ey;
                    cout<<a[ex][ey] - a[sx-1][ey] - a[ex][sy-1]   + a[sx-1][sy-1]<<endl;
                }
                return 0;
            }
            
            
            
            • 0
              @ 2024-5-21 17:21:32

              最简代码@man!

              #include<bits/stdc++.h>
              using namespace std;
              long long n,m,k,a[10010][10010],s[10010][10010];
              int main(){
              	cin>>n>>m>>k;
              	for(int i=1;i<=n;i++)for(int j=1;j<=m;j++){
              		cin>>a[i][j];s[i][j]=s[i-1][j]+s[i][j-1]-s[i-1][j-1]+a[i][j];
              	}
              	while(k--){
              		int i,j,p,q;cin>>i>>j>>p>>q;cout<<s[p][q]-s[p][j-1]-s[i-1][q]+s[i-1][j-1]<<endl;
              	}
              	return 0;
              }
              
              • -2
                @ 2021-12-18 19:34:06
                #include <iostream>
                #include <stdio.h>
                #include <string.h>
                #include <queue>
                #include <math.h>
                #include <vector>
                #include <algorithm>
                #include <iomanip>
                #include <stack>
                
                using namespace std;
                
                #define LL long long
                const int N =1e5+10;
                const int INF =0x3f3f3f3f;
                int a[1001][1001];
                int main(){
                    int n,m,t,x1,y1,x2,y2;
                    cin>>n>>m>>t;
                    for(int i=1;i<=n;i++){
                        for(int j=1;j<=m;j++){
                            cin>>a[i][j];
                            a[i][j]+=a[i-1][j]+a[i][j-1]-a[i-1][j-1];
                        }
                    }
                    while(t--){
                        cin>>x1>>y1>>x2>>y2;
                        cout<<a[x2][y2]-a[x1-1][y2]-a[x2][y1-1]+a[x1-1][y1-1]<<endl;
                    }
                return 0;
                }
                
                • -3
                  @ 2022-9-26 16:24:09
                  #include<iostream> 
                  using namespace std;
                  int n,m,k,a[1005][1005],b[1005][1005],x1,x2,y1,y2;
                  int main(){
                  	cin>>n>>m>>k;
                  	for(int i=1;i<=n;i++){
                  		for(int j=1;j<=m;j++){
                  			cin>>a[i][j];
                  			b[i][j]=b[i-1][j]+b[i][j-1]-b[i-1][j-1]+a[i][j]; \\构造前缀和二维数组
                  		}
                  	}
                  		for(int i=1;i<=k;i++){
                  			cin>>x1>>y1>>x2>>y2;
                  			cout<<b[x2][y2]-b[x2][y1-1]-b[x1-1][y2]+b[x1-1][y1-1]<<endl;\\代入公式
                  		}
                  }
                  
                  • 1

                  信息

                  ID
                  1283
                  时间
                  1000ms
                  内存
                  256MiB
                  难度
                  6
                  标签
                  递交数
                  649
                  已通过
                  208
                  上传者