5 条题解

  • 1
    #include<iostream>
    #include<stdio.h> 
    #include<string.h> 
    #include<queue> 
    #include<math.h>
    #include<vector> 
    #include<algorithm> 
    #include<iomanip> 
    #include<stack>
    #include<cmath>
    using namespace std;
    bool pdss(int x){
    	bool flag=1;
    	for(int i=2;i<=sqrt(x);i++){
    		if(x%i==0){
    			flag=0;
    			break;
    		}
    
    	}	
    	return flag;
    }
    int main(){
    	int n;
    	cin>>n;
    	if(pdss(n)==1&&n>1)cout<<"Yes";
    	else cout<<"No";	
    }
    
    • 1
      @ 2023-4-22 12:17:07

      #include<iostream> #include<cmath> using namespace std; int main() { int n; bool sum=1; cin>>n; for(int i=2;i<=sqrt(n);i++){ if(n%i0) { sum=0; break; } } if(sum1&&n>1)cout<<"Yes"; else cout<<"No"; return 0; }


      • 1
        @ 2021-11-29 22:19:26

        注意n=1时要特判

        n = int(input())
        ok=1
        for i in range(2,n):
            if i*i>n:
                break
            elif n%i==0:
                print("No")
                ok=0
                break
        if(ok and n!=1):
            print('Yes')
        if n==1:
            print('No')
        
        • 0
          @ 2023-5-21 18:20:24
          import math
          n=int(input())
          zhishu=True
          if n==1:
              print("No")
          elif n==2 or n==3:
              print("Yes")
          elif n>3:
              i=3;
              while(i<=int(math.sqrt(n))+1):
                  if n%i==0:
                      print("No")
                      zhishu=False
                      break
                  i+=2;
              if zhishu:
                  print("Yes")
          
          • -2
            @ 2021-12-11 22:13:41
            import math
            n=int(input())
            zhishu=True
            if n==1:
                print("No")
            elif n==2 or n==3:
                print("Yes")
            elif n>3:
                i=3;
                while(i<=int(math.sqrt(n))+1):
                    if n%i==0:
                        print("No")
                        zhishu=False
                        break
                    i+=2;
                if zhishu:
                    print("Yes")
            
            • 1

            信息

            ID
            1366
            时间
            1000ms
            内存
            128MiB
            难度
            7
            标签
            递交数
            570
            已通过
            111
            上传者