1 条题解
- 
  2
C++ :
#include<bits/stdc++.h> using namespace std; const int N = 105, M = 1e5 + 10; int g[M], a[N], c[N]; bool f[M]; int n, m; int main() { while (scanf("%d%d", &n, &m), n || m) { for (int i = 1; i <= n; i++) scanf("%d", &a[i]); for (int i = 1; i <= n; i++) scanf("%d", &c[i]); memset(f, 0, sizeof(f)); f[0] = true; for (int i = 1; i <= n; i++) { memset(g, 0, sizeof(g)); for (int j = a[i]; j <= m; j++) { if (!f[j] && f[j - a[i]] && g[j - a[i]] < c[i]) f[j] = true, g[j] = g[j - a[i]] + 1; } } int res = 0; for (int i = 1; i <= m; i++)if (f[i])res++; printf("%d\n", res); } return 0; } 
- 1
 
信息
- ID
 - 192
 - 时间
 - 1000ms
 - 内存
 - 128MiB
 - 难度
 - 6
 - 标签
 - 递交数
 - 21
 - 已通过
 - 11
 - 上传者