21 条题解

  • 4
    @ 2025-5-11 9:42:17 
    #include<bits/stdc++.h>
using namespace std;
int main(){
    long long a,b,p,res=1;
    scanf("%ld%ld%ld",&a,&b,&p);
    while(b!=0){
        if(b&1){
            res=res*a%p;
        }
        a=a*a%p;
        b>>=1;
    }
    printf("%ld\n",res%p);
    return 0;
}
    • 2
      @ 2026-5-31 17:31:58

      一定AC

      using namespace std;
int a,b,p;
int quicky_pow(int a,int b,int md)
{
	int res = 1;
	while(b)
	{
		if(b%2==1)
		{
			res = (long long)res*a%md;
		}
		b/=2;
		a=(long long)a*a%md;
	}
	return res%md;
}
int main()
{
	cin >> a >> b >> p;
	cout<<quicky_pow(a,b,p);
	return 0;	
}
    • 2
      @ 2026-4-19 15:30:45

      老师眼中的魔术

      #include<bits/stdc++.h>
using namespace std;
    int a,b,p;
    int quick_pow(int a,int b,int md){
        int res=1;
        while(b){
            if(b%2==1)
                res=(long long)res*a%md;
            b/=2;
            a=(long long)a*a%md;
        }
        return res%md;
    }
int main()
{
    cin>>a>>b>>p;
    cout<<quick_pow(a,b,p);
    return 0;
}
      • 2
        @ 2025-5-10 9:52:48

        分治

        #include<bits/stdc++.h>
using namespace std;
const int N=1e5+5,INF=0x3f3f3f3f;
typedef long long LL;
typedef unsigned long long ULL;
ULL a,b,p; 
ULL f(ULL a,ULL b){
	if(b==0)return 1%p;
	if(b==1)return a%p;
	if(b&1)return a*f(a*a%p,b/2)%p;
	return f(a*a%p,b/2)%p;
}
int main()
{
	cin>>a>>b>>p;
	cout<<f(a,b)%p;
	return 0;
}
        • @ 2025-5-11 15:15:25

          666，盐都不盐了，直接把张老师教的代码搬过来了

        • @ 2025-12-28 10:24:07

          是张正标老师吗？

      • 1
        @ 2025-3-5 17:31:30

        快速幂模版

        #include<bits/stdc++.h>
using namespace std;
const int N=1e5+5,INF=0x3f3f3f3f;
typedef long long LL;
LL a,b,p; 
LL power(){
	LL ans=1;
	while(b){
		if(b&1)ans = ans*a%p;
		b>>=1;
		a = a*a%p;
	}
	return ans%p;
}
int main()
{
	cin>>a>>b>>p;
	cout<<power();
	return 0;
}
      • 0
        @ 2026-7-4 16:48:53

        #include #include #include #include #include using namespace std;

        typedef long long ll; const int MAXN = 55; const int MAXK = 3; const ll INF = -1e18;

        int n; int g[MAXN][MAXN]; vector vals;

        ll dp[MAXN][MAXN][MAXK + 1];

        vector calc_max(int limit_val, bool is_A) { int max_t = is_A ? MAXK : n * n; for (int i = 0; i < n; ++i) for (int j = 0; j < n; ++j) for (int k = 0; k <= MAXK; ++k) dp[i][j][k] = INF;

        int st = g[0][0];
if (st != 0) {
    if ((is_A && st > limit_val) || (!is_A && st < limit_val)) {
        dp[0][0][1] = st;
    }
}
dp[0][0][0] = 0;

for (int i = 0; i < n; ++i) {
    for (int j = 0; j < n; ++j) {
        if (i == 0 && j == 0) continue;
        int cur = g[i][j];
        bool ok = false;
        if (cur != 0) {
            if ((is_A && cur > limit_val) || (!is_A && cur < limit_val))
                ok = true;
        }
        if (i > 0) {
            for (int k = 0; k <= MAXK; ++k) {
                if (dp[i-1][j][k] == INF) continue;
                if (dp[i][j][k] < dp[i-1][j][k])
                    dp[i][j][k] = dp[i-1][j][k];
                if (ok && k + 1 <= MAXK) {
                    if (dp[i][j][k+1] < dp[i-1][j][k] + cur)
                        dp[i][j][k+1] = dp[i-1][j][k] + cur;
                }
            }
        }
        if (j > 0) {
            for (int k = 0; k <= MAXK; ++k) {
                if (dp[i][j-1][k] == INF) continue;
                if (dp[i][j][k] < dp[i][j-1][k])
                    dp[i][j][k] = dp[i][j-1][k];
                if (ok && k + 1 <= MAXK) {
                    if (dp[i][j][k+1] < dp[i][j-1][k] + cur)
                        dp[i][j][k] + cur;
                    dp[i][j][k+1] = max(dp[i][j][k+1], dp[i][j-1][k] + cur);
                }
            }
        }
    }
}
vector<ll> res(MAXK + 1, INF);
for (int k = 0; k <= MAXK; ++k)
    res[k] = dp[n-1][n-1][k];
return res;

        }

        int main() { freopen("StarPick.in","w",stdin); freopen("StarPick.out","r",stdout); ios::sync_with_stdio(false); cin.tie(0); cin >> n; set s; for (int i = 0; i < n; ++i) { for (int j = 0; j < n; ++j) { cin >> g[i][j]; if (g[i][j] != 0) s.insert(g[i][j]); } } for (int x : s) vals.push_back(x); ll ans = 0; for (int mid : vals) { auto a = calc_max(mid, true);
        auto b = calc_max(mid, false); for (int ka = 1; ka <= 3; ++ka) { if (a[ka] == INF) continue; for (int kb = 0; kb <= ka; ++kb) { if (b[kb] == INF) continue; ans = max(ans, a[ka] + b[kb]); } } } cout << ans << endl; return 0; }

        • 0
          @ 2026-7-4 16:48:47

          #include <bits/stdc++.h> using namespace std; long long a, b; long long n; long long ans; int main() { freopen("SegCount.in","w",stdin); freopen("SegCount.out","r",stdout); cin >> a >> b; n=a+b; while(n!=0) { int sum=n%10; n/=10; if(sum0) { ans+=6; } else if(sum1) { ans+=2; } else if(sum2) { ans+=5; } else if(sum3) { ans+=5; } else if(sum4) { ans+=4; } else if(sum5) { ans+=5; } else if(sum6) { ans+=6; } else if(sum7) { ans+=3; } else if(sum8) { ans+=7; } else if(sum9) { ans+=5; } } cout << ans; }

          • 0
            @ 2026-7-4 16:48:37

            #include <bits/stdc++.h> using namespace std; long long t; int main() { freopen("LoopPatrol.in","w",stdin); freopen("LoopPatrol.out","r",stdout); long long x=0, y=0, a=0, b=0; string s; cin >> s; cin >> t; int i=s.size(); for(int j = 0; j < i; ++j) { char c = s[j]; if (c=='E') { x++; } else if(c=='W') { x--; } else if(c=='N') { y++; } else if(c=='S') { y--; } } long long f=t/i; long long r=t%i; a=fx; b=fy; for (int j = 0; j < r; ++j) { char c = s[j]; if (c=='E') { a++; } else if(c=='W') { a--; } else if(c=='N') { b++; } else if(c=='S') { b--; } } cout << a << " " << b; return 0; }

            • 0
              @ 2026-6-24 11:56:53 
              using namespace std;
long long a,b,p;
long long  quickpow(long long a,long long b){
	int res=1;
	while(b>0){
		if(b%2==1){
			res=res*a%p;
		}
		b/=2;
		a=a*a%p;
	}
	return res%p;
}
int main(){
    cin>>a>>b>>p;
    cout<<quickpow(a,b);
    return 0;
}
              • 0
                @ 2026-6-24 11:56:13

                #include<bits/stdc++.h> using namespace std; long long a,b,p; long long quickpow(long long a,long long b){ int res=1; while(b>0){ if(b%2==1){ res=res*a%p; } b/=2; a=a*a%p; } return res%p; } int main(){ cin>>a>>b>>p; cout<<quickpow(a,b); return 0; }

                • 0
                  @ 2025-5-10 9:32:02 
                  #include<bits/stdc++.h>
using namespace std;
long long a, b,c ,p,ans=1,cnt;
int main(){
	cin>>a>>b>>p;
	cnt=a;
	while(b!=c){
		if(b%2==1){
		ans=ans*cnt%p;
		}
		cnt=cnt*cnt%p;
		b/=2;
	}
	cout<<ans%p;
	return 0;
}
//迪奥代码
                  • 0
                    @ 2025-5-10 9:30:28 
                    #include<bits/stdc++.h>
using namespace std;
const int N=1e5+5,INF=0x3f3f3f3f;
typedef long long LL;
LL a,b,p; 
LL power(){
	LL ans=1;
	while(b){
		if(b&1)ans = ans*a%p;
		a = a*a%p,b>>=1;
	}
	return ans%p;
}
int main()
{
	cin>>a>>b>>p;
	cout<<power();
	return 0;
}
                    • 0
                      @ 2025-5-10 9:30:03 
                      #include<bits/stdc++.h>
using namespace std;
#define LL long long
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
long long power( long long n , long long m , long long p )
{
	if ( n == 0 )
	{
		return 0;
	}
	long long ans = 1;
	while ( m )
	{
		if ( m & 1 )
		{
			ans = ( ans * n ) % p;
		}
		m >>= 1;
		n = ( n * n ) % p;
	}
	return ans % p;
}
int main()
{
	long long n , m , p;
	cin >> n >> m >> p;
	cout << power( n , m , p );
	return 0;
}
//菜鸟驿站
//老六专属
                      • 0
                        @ 2025-5-10 9:29:31 
                        #include<bits/stdc++.h>
using namespace std;
#define LL long long
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
long long power( long long n , long long m , long long p )
{
	if ( n == 0 )
	{
		return 0;
	}
	long long ans = 1;
	while ( m )
	{
		if ( m & 1 )
		{
			ans = ( ans * n ) % p;
		}
		m >>= 1;
		n = ( n * n ) % p;
	}
	return ans % p;
}
int main()
{
	long long n , m , p;
	cin >> n >> m >> p;
	cout << power( n , m , p );
	return 0;
}
//菜鸟驿站
//老六专属
                        • 0
                          @ 2025-4-21 20:21:14 
                          
cpp
```

#include <bits/stdc++.h>
using namespace std;
#define LL long long
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
long long power( long long n , long long m , long long p )
{
	if ( n == 0 )
	{
		return 0;
	}
	long long ans = 1;
	while ( m )
	{
		if ( m & 1 )
		{
			ans = ( ans * n ) % p;
		}
		m >>= 1;
		n = ( n * n ) % p;
	}
	return ans % p;
}
int main()
{
	long long n , m , p;
	cin >> n >> m >> p;
	cout << power( n , m , p );
	return 0;
}
//菜鸟驿站
//老六专属
```
                          • -1
                            @ 2026-3-27 15:16:23 
                            #include <bits/stdc++.h>
using namespace std;

int main(){
	long long a, b, t = 1, p;
	cin >> a >> b >> p;
	while(b){
		if(b & 1) t = (t * a) % p;
		b >>= 1;
		a = (a * a) % p;
	}
	cout << t % p << endl;
	return 0;
}
                            • -3
                              @ 2025-5-10 9:30:35

                              #include #include

                              include

                              #include #include #include #include const int N=1e2+10; const int INF =0x3f3f3f3f; using namespace std; unsigned long long a,b,p; int power(int a,int b,int p){ long long ans=1; long long wq=a; while(b){ if(b&1){ ans=ans*wq%p;

                              	}
	b>>=1;
	wq=wq*wq%p;

}
return ans %p;

                              } int main(){ cin>>a>>b>>p; cout<<power(a,b,p); }

                              • -3
                                @ 2025-1-25 11:33:34 
                                ```
#include<iostream>
using namespace std;

int main()
{
    long long a, b, p, res = 1;
    scanf ("% ld % ld % ld", &a, &b, &p);
    while (b != 0)
   {
        if (b & 1)
        {
            res = res * a % p;
        }
        a = a * a % p;
        b >>= 1;
    }
    printf ("% ld \ n", res % p);
    return 0;
}
```
                                • -3
                                  @ 2024-11-19 20:21:06 
                                  #include<bits/stdc++.h>
using namespace std;
int main(){
    long long a,b,p,res=1;
    scanf("%ld%ld%ld",&a,&b,&p);
    while(b!=0){
        if(b&1){
            res=res*a%p;
        }
        a=a*a%p;
        b>>=1;
    }
    printf("%ld\n",res%p);
    return 0;
}
                                  • -6
                                    @ 2024-10-17 21:24:34

                                    知识点：快速幂

                                    /*
int      %o/%lo(八进制) %d/%i/%ld/%li(十进制) %x/%lx(十六进制)[如标名为o/lo/d/i/lo/li/x/lx即输出为八进制/十进制/十六进制]
longlong %lld
float    %f/%e
double   %lf/%le
char     %c
char[]   %s
'a'=97
'z'=122
'A'=65
'Z'=90
'0'=48
'9'=57
*/
#include <iostream>
#include <iomanip>
#include <cmath>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <ctime>
#include <limits>
#include <assert.h>
#include <stdlib.h>
using namespace std;
#define LL long long
#define ull unsigned long long
const int N=1e5+10;
const int INF=0x3f3f3f3f;
const double pi=3.1416;
LL a,b,p;
long long power(long long a,long long b,long long p){
	long long ans=1;
	long long wp=a;
	while(b){
		if(b&1){
			ans=ans*wp%p;
		}
		b>>=1;
		wp=wp*wp%p;
	}
	return ans%p;
}
int main(){
	cin>>a>>b>>p;
	cout<<power(a,b,p)<<endl;
return 0;
}

                                  a^b

                                  信息

                                  ID
                                  2
                                  时间
                                  1000ms
                                  内存
                                  128MiB
                                  难度
                                  8
                                  标签
                                  递交数
                                  3736
                                  已通过
                                  602
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