5 条题解

  • 0
    @ 2023-12-29 17:19:53

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    • 0
      @ 2023-5-13 12:02:22

      #include<cstdio> #include<iostream> #include<algorithm> #include<cstring> using namespace std; const int MAXN = 1e5 + 10;

      int n,lens = 1,lenm = 1,lena = 1; int sum[MAXN] = {0,1}, Max[10010] = {0, 1}, ans[MAXN]; struct node{ long long l, r, all; void read(){ cin >> l >> r; all = l * r; } }coin[MAXN]; bool operator< (node a,node b){ return a.all < b.all; } void mul(long long x){ int tmp = 0; for(int i = 1;i <= lens; i++){ sum[i] *= x; } for(int i = 1;i <= lens; i++){ tmp += sum[i]; sum[i] = tmp % 10; tmp /= 10; } while(tmp != 0){ lens++; sum[lens] = tmp % 10; tmp /= 10; } } void work(long long x){ memset(ans, 0, sizeof(ans)); lena = lens; int tmp = 0; for(int i = lena; i >= 1; i--){ tmp *= 10; tmp += sum[i]; if(tmp >= x){ ans[i] = tmp / x; tmp %= x; } } while(ans[lena] == 0){ if(lena == 1){ break; } lena--; } } void chose(){ if(lena > lenm) { for(int i = 1;i <= lena; i++){ Max[i] = ans[i]; } lenm = lena; } else if(lena == lenm){ for(int i = lena;i >= 1; i--){ if(Max[i] < ans[i]){ for(int j = 1;j <= lena; j++){ Max[j] = ans[j]; } lenm = lena; break; } } } } int main(){ cin >> n; cin >> coin[0].l >> coin[0].r; for(int i = 1;i <= n; i++){ coin[i].read(); } sort(coin + 1, coin + n + 1); for(int i = 1;i <= n; i++){ mul(coin[i - 1].l); work(coin[i].r); chose(); } for(int i = lenm; i >= 1; i--){ cout << Max[i]; } return 0; }

      • 0
        @ 2022-2-11 17:40:42
        #include<cstdio>
        #include<iostream>
        #include<algorithm>
        #include<cstring>
        using namespace std;
        const int MAXN = 1e5 + 10;
        
        int n,lens = 1,lenm = 1,lena = 1;
        int sum[MAXN] = {0,1}, Max[10010] = {0, 1}, ans[MAXN];
        struct node{
        	long long l, r, all;
        	void read(){
        		cin >> l >> r;
        		all = l * r;
        	}
        }coin[MAXN];
        bool operator< (node a,node b){
        	return a.all < b.all;
        }
        void mul(long long x){
        	int tmp = 0;
        	for(int i = 1;i <= lens; i++){
        		sum[i] *= x;
        	}
        	for(int i = 1;i <= lens; i++){
        		tmp += sum[i];
        		sum[i] = tmp % 10;
        		tmp /= 10;
        	}
        	while(tmp != 0){
        		lens++;
        		sum[lens] = tmp % 10;
        		tmp /= 10;
        	}
        }
        void work(long long x){
        	memset(ans, 0, sizeof(ans));
        	lena = lens;
        	int tmp = 0;
        	for(int i = lena; i >= 1; i--){
        		tmp *= 10;
        		tmp += sum[i];
        		if(tmp >= x){
        			ans[i] = tmp / x;
        			tmp %= x;
        		}
        	}
        	while(ans[lena] == 0){
        		if(lena == 1){
        			break;
        		}
        		lena--;
        	}
        }
        void chose(){
        	if(lena > lenm) {
        		for(int i = 1;i <= lena; i++){
        			Max[i] = ans[i];
        		}
        		lenm = lena;
        	}
        	else if(lena == lenm){
        		for(int i = lena;i >= 1; i--){
        			if(Max[i] < ans[i]){
        				for(int j = 1;j <= lena; j++){
        					Max[j] = ans[j];
        				}
        				lenm = lena;
        				break;
        			}
        		}
        	}
        }
        int main(){
        	cin >> n;
        	cin >> coin[0].l >> coin[0].r;
        	for(int i = 1;i <= n; i++){
        		coin[i].read();
        	}
        	sort(coin + 1, coin + n + 1);
        	for(int i = 1;i <= n; i++){
        		mul(coin[i - 1].l);
        		work(coin[i].r);
        		chose();
        	}
        	for(int i = lenm; i >= 1; i--){
        		cout << Max[i];
        	}
        	return 0;
        }
        
        • 0
          @ 2021-8-7 18:41:43

          C++ :

          #include <iostream>
          #include <algorithm>
          #include <vector>
          
          using namespace std;
          
          typedef pair<int, int>PII;
          const int N = 1010;
          
          int n;
          PII ps[N];
          
          vector<int> mul(vector<int> a, int b) //高精度乘法
          {
              vector<int> c;
              int t = 0;
              for(int i = 0; i < a.size(); i++)
              {
                  t += a[i] * b;
                  c.push_back(t % 10); //取出余数
                  t /= 10; //进位
              }
              while(t) c.push_back(t % 10), t /= 10;
              return c; 
          }
          
          vector<int> div(vector<int> a, int b)
          {
              vector<int> c;
              bool is_first = false; // 避免输出前面位的0
              for(int i = a.size() - 1, t = 0; i >= 0; i--) //从高位往低位
              {
                  t = t * 10 + a[i]; //竖式后位的值
                  int x = t / b;
                  if(x || is_first)
                  {
                      is_first  = true;
                      c.push_back(x);
                  }
                  t %= b;
              }
              return vector<int>(c.rbegin(), c.rend()); //逆序遍历
          }
          
          vector<int> max_vec(vector<int>a, vector<int> b) // 返回vector
          {
              if(a.size() > b.size()) return a;
              if(a.size() < b.size()) return b;
              if(vector<int>(a.rbegin(), a.rend()) > vector<int>(b.rbegin(), b.rend()))//构造新的vector,是a的逆序
                  return a;
              return b;    
          }
          
          void output(vector<int> a)
          {
              for(int i = a.size() - 1; i >= 0; i--) cout << a[i]; //高精度存,小位在前,高位在后,因为增加一位只能在后面增加
              cout << endl;
          }
          
          int main()
          {
              cin >> n;
              for(int i = 0; i <= n; i++) // 0位国王,1...n+1为大臣
              {
                  int a, b;
                  cin >> a >> b;
                  ps[i] = {a * b, a};
              }
              sort(ps + 1, ps + n + 1);
              
              vector<int>product(1, 1); //乘积长度为1,初始为1
              vector<int>res(1,0); // 结果长度为1,初始为0
              
              for(int i = 0; i <= n; i++)
              {
                  if(i) res = max_vec(res, div(product, ps[i].first / ps[i].second));
                  product = mul(product, ps[i].second);
              }
              
              output(res);
              return 0;
          }
          
          • -1
            @ 2022-7-20 12:01:58
            #include<cstdio>
            #include<iostream>
            #include<algorithm>
            #include<cstring>
            using namespace std;
            const int MAXN = 1e5 + 10;
            
            int n,lens = 1,lenm = 1,lena = 1;
            int sum[MAXN] = {0,1}, Max[10010] = {0, 1}, ans[MAXN];
            struct node{
            	long long l, r, all;
            	void read(){
            		cin >> l >> r;
            		all = l * r;
            	}
            }coin[MAXN];
            bool operator< (node a,node b){
            	return a.all < b.all;
            }
            void mul(long long x){
            	int tmp = 0;
            	for(int i = 1;i <= lens; i++){
            		sum[i] *= x;
            	}
            	for(int i = 1;i <= lens; i++){
            		tmp += sum[i];
            		sum[i] = tmp % 10;
            		tmp /= 10;
            	}
            	while(tmp != 0){
            		lens++;
            		sum[lens] = tmp % 10;
            		tmp /= 10;
            	}
            }
            void work(long long x){
            	memset(ans, 0, sizeof(ans));
            	lena = lens;
            	int tmp = 0;
            	for(int i = lena; i >= 1; i--){
            		tmp *= 10;
            		tmp += sum[i];
            		if(tmp >= x){
            			ans[i] = tmp / x;
            			tmp %= x;
            		}
            	}
            	while(ans[lena] == 0){
            		if(lena == 1){
            			break;
            		}
            		lena--;
            	}
            }
            void chose(){
            	if(lena > lenm) {
            		for(int i = 1;i <= lena; i++){
            			Max[i] = ans[i];
            		}
            		lenm = lena;
            	}
            	else if(lena == lenm){
            		for(int i = lena;i >= 1; i--){
            			if(Max[i] < ans[i]){
            				for(int j = 1;j <= lena; j++){
            					Max[j] = ans[j];
            				}
            				lenm = lena;
            				break;
            			}
            		}
            	}
            }
            int main(){
            	cin >> n;
            	cin >> coin[0].l >> coin[0].r;
            	for(int i = 1;i <= n; i++){
            		coin[i].read();
            	}
            	sort(coin + 1, coin + n + 1);
            	for(int i = 1;i <= n; i++){
            		mul(coin[i - 1].l);
            		work(coin[i].r);
            		chose();
            	}
            	for(int i = lenm; i >= 1; i--){
            		cout << Max[i];
            	}
            	return 0;
            }
            
            • 1

            信息

            ID
            25
            时间
            1000ms
            内存
            128MiB
            难度
            1
            标签
            递交数
            134
            已通过
            101
            上传者