1 条题解
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0昌孝阳 (changxiaoyang) LV 10 @ 2024-1-25 17:10:22
#include <cstdio> #include <cmath> #include <algorithm> #include <cstring> #include <set> #define LL long long #define N 100010 using namespace std; set<int> s; typedef set<int>::iterator It; struct info { int to, nex, w; } e[N * 2]; int n, m, _log, tot, head[N * 2]; int dep[N], f[N][20], p[N], dfn[N]; LL dis[N][20], Ans; inline int read() { int x = 0, f = 1; char ch = getchar(); while (ch < '0' || ch > '9') {if (ch == '-')f = -1; ch = getchar();} while (ch >= '0' && ch <= '9') {x = x * 10 + ch - '0'; ch = getchar();} return x * f; } inline void add_edge(int u, int v, int w) { e[++tot].to = v; e[tot].nex = head[u]; head[u] = tot; e[tot].w = w; } void dfs(int u, int fa) { for (int i = 1; i <= _log; ++i) { f[u][i] = f[f[u][i - 1]][i - 1]; dis[u][i] = dis[u][i - 1] + dis[f[u][i - 1]][i - 1]; } for (int i = head[u]; i; i = e[i].nex) { int v = e[i].to; if (v == fa) continue; f[v][0] = u; dis[v][0] = e[i].w; dep[v] = dep[u] + 1; dfs(v, u); } } LL LCA(int u, int v) { LL res = 0; if (dep[u] > dep[v]) swap(u, v); int d = dep[v] - dep[u]; for (int i = 0; i <= _log; ++i) if (d & (1 << i)) res += dis[v][i], v = f[v][i]; if (u == v) return res; for (int i = _log; i >= 0; i--) if (f[u][i] != f[v][i]) { res += dis[u][i] + dis[v][i]; u = f[u][i]; v = f[v][i]; } return res + dis[u][0] + dis[v][0]; } void dddfs(int u) { dfn[u] = ++tot; p[tot] = u; for (int i = head[u]; i; i = e[i].nex) { int v = e[i].to; if (!dfn[v]) dddfs(v); } } inline It L(It it) { if (it == s.begin()) return --s.end(); return --it; } inline It R(It it) { if (it == --s.end()) return s.begin(); return ++it; } int main() { n = read(); _log = log(n) / log(2); for (int i = 1; i < n; ++i) { int u = read(), v = read(), w = read(); add_edge(u, v, w); add_edge(v, u, w); } dfs(1, 0); tot = 0; dddfs(1); m = read(); while (m--) { int ch = getchar(); while (ch != '+' && ch != '-' && ch != '?') ch = getchar(); It it; int t; if (ch == '?') printf("%lld\n", Ans / 2); else { int x = read(); if (ch == '+') { if (s.size()) { it = s.lower_bound(dfn[x]); if (it == s.end()) it = s.begin(); t = *L(it); Ans += LCA(x, p[t]) + LCA(x, p[*it]) - LCA(p[t], p[*it]); } s.insert(dfn[x]); } else { it = s.find(dfn[x]); t = *L(it), it = R(it); Ans -= LCA(x, p[t]) + LCA(x, p[*it]) - LCA(p[t], p[*it]); s.erase(dfn[x]); } } } return 0; }
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信息
- ID
- 265
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 9
- 标签
- 递交数
- 9
- 已通过
- 8
- 上传者