1 条题解
-
1莫言 (slz莫言) LV 10 @ 2024-12-18 13:00:44
#include <bits/stdc++.h> #define int long long using namespace std; const int INF = 0x3f3f3f3f; const int N = 1e6 + 10; int n , m , x , l , r; int a [N]; signed main() { cin >> n >> m; for(int i = 1; i <= n; i++) { cin >> x; a [i] = a [i - 1] + x; } for(int i = 1; i <= m; i++) { cin >> l >> r; cout << a [r] - a [l - 1] << "\n"; } return 0; }
- 1
信息
- ID
- 3146
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 1
- 标签
- (无)
- 递交数
- 28
- 已通过
- 14
- 上传者