5 条题解

  • 0
    @ 2026-5-2 8:10:16
    #include <bits/stdc++.h>
    #define LL long long
    using namespace std;
    const int N = 1010;
    int n, m;
    char g[N][N];
    int dx[4] = {-1, 1, 0, 0};
    int dy[4] = {0, 0, -1, 1};
    
    bool f(int x, int y) {
        if (g[x][y] != '.') return false;
        for (int i = 0; i < 4; i++) {
            int nx = x + dx[i], ny = y + dy[i];
            if (nx < 1 || nx > n || ny < 1 || ny > m) continue;
            if (g[nx][ny] == '#') return false;
        }
        return true;
    }
    
    int add(int x0, int y0) {
        if (g[x0][y0] != '#') return 0;
        int res = 0;
        bool self_ok = true;
        for (int i = 0; i < 4; i++) {
            int nx = x0 + dx[i], ny = y0 + dy[i];
            if (nx < 1 || nx > n || ny < 1 || ny > m) continue;
            if (g[nx][ny] == '#') {
                self_ok = false;
                break;
            }
        }
        if (self_ok) res++;
        for (int i = 0; i < 4; i++) {
            int nx = x0 + dx[i], ny = y0 + dy[i];
            if (nx < 1 || nx > n || ny < 1 || ny > m) continue;
            if (g[nx][ny] != '.') continue;
            bool origin_bad = false;
            for (int j = 0; j < 4; j++) {
                int nnx = nx + dx[j], nny = ny + dy[j];
                if (nnx < 1 || nnx > n || nny < 1 || nny > m) continue;
                if (g[nnx][nny] == '#' && (nnx != x0 || nny != y0)) {
                    origin_bad = true;
                    break;
                }
            }
            if (!origin_bad && !f(nx, ny)) {
                res++;
            }
        }
        return res;
    }
    
    int main() {
        cin >> n >> m;
        for (int i = 1; i <= n; i++) {
            string s; cin >> s;
            for (int j = 1; j <= m; j++) {
                g[i][j] = s[j-1];
            }
        }
        int base = 0;
        for (int i = 1; i <= n; i++) {
            for (int j = 1; j <= m; j++) {
                if (f(i, j)) base++;
            }
        }
        int max_add = 0;
        for (int i = 1; i <= n; i++) {
            for (int j = 1; j <= m; j++) {
                if (g[i][j] == '#') {
                    max_add = max(max_add, add(i, j));
                }
            }
        }
        cout << base + max_add << endl;
        return 0;
    }
    //:)
    //114514
    
    • 0
      @ 2026-4-6 9:02:18

      虽然只有一种味道,但真的很 鲜~

      葵花籽味

      #include <iostream>
      #include <vector>
      #include <string>
      using namespace std;
      inline bool in(int x, int y, int n, int m) {
          return x >= 0 && x < n && y >= 0 && y < m;
      }
      inline bool good(const vector<string>& g, int x, int y, int n, int m) {
          const int d[4][2] = {{-1,0},{1,0},{0,-1},{0,1}};
          for (int i = 0; i < 4; i++) {
              int nx = x + d[i][0], ny = y + d[i][1];
              if (in(nx, ny, n, m) && g[nx][ny] == '#')
                  return false;
          }
          return true;
      }
      inline bool goodAfter(const vector<string>& g, int x, int y, int cx, int cy, int n, int m) {
          const int d[4][2] = {{-1,0},{1,0},{0,-1},{0,1}};
          for (int i = 0; i < 4; i++) {
              int nx = x + d[i][0], ny = y + d[i][1];
              if ((nx == cx && ny == cy) || !in(nx, ny, n, m))
                  continue;
              if (g[nx][ny] == '#')
                  return false;
          }
          return true;
      }
      
      int main() {
          int n, m;
          cin >> n >> m;
          vector<string> g(n);
          for (int i = 0; i < n; i++) cin >> g[i];
          int orig = 0;
          for (int i = 0; i < n; i++)
              for (int j = 0; j < m; j++)
                  if (g[i][j] == '.' && good(g, i, j, n, m))
                      orig++;
          
          int maxAdd = 0;
          const int d[4][2] = {{-1,0},{1,0},{0,-1},{0,1}};
          for (int i = 0; i < n; i++) {
              for (int j = 0; j < m; j++) {
                  if (g[i][j] == '#') {
                      int add = 0;
                      if (goodAfter(g, i, j, i, j, n, m)) add++;
                      for (int k = 0; k < 4; k++) {
                          int x = i + d[k][0], y = j + d[k][1];
                          if (in(x, y, n, m) && g[x][y] == '.') {
                              if (!good(g, x, y, n, m) && goodAfter(g, x, y, i, j, n, m))
                                  add++;
                          }
                      }
                      maxAdd = max(maxAdd, add);
                  }
              }
          }
          
          cout << orig + maxAdd << endl;
          return 0;
      }
          
      
      
      
      • 0
        @ 2026-3-20 19:13:04
        #include <iostream>
        #include <vector>
        #include <string>
        using namespace std;
        inline bool in(int x, int y, int n, int m) {
            return x >= 0 && x < n && y >= 0 && y < m;
        }
        inline bool good(const vector<string>& g, int x, int y, int n, int m) {
            const int d[4][2] = {{-1,0},{1,0},{0,-1},{0,1}};
            for (int i = 0; i < 4; i++) {
                int nx = x + d[i][0], ny = y + d[i][1];
                if (in(nx, ny, n, m) && g[nx][ny] == '#')
                    return false;
            }
            return true;
        }
        inline bool goodAfter(const vector<string>& g, int x, int y, int cx, int cy, int n, int m) {
            const int d[4][2] = {{-1,0},{1,0},{0,-1},{0,1}};
            for (int i = 0; i < 4; i++) {
                int nx = x + d[i][0], ny = y + d[i][1];
                if ((nx == cx && ny == cy) || !in(nx, ny, n, m))
                    continue;
                if (g[nx][ny] == '#')
                    return false;
            }
            return true;
        }
        
        int main() {
            int n, m;
            cin >> n >> m;
            vector<string> g(n);
            for (int i = 0; i < n; i++) cin >> g[i];
            int orig = 0;
            for (int i = 0; i < n; i++)
                for (int j = 0; j < m; j++)
                    if (g[i][j] == '.' && good(g, i, j, n, m))
                        orig++;
            
            int maxAdd = 0;
            const int d[4][2] = {{-1,0},{1,0},{0,-1},{0,1}};
            for (int i = 0; i < n; i++) {
                for (int j = 0; j < m; j++) {
                    if (g[i][j] == '#') {
                        int add = 0;
                        if (goodAfter(g, i, j, i, j, n, m)) add++;
                        for (int k = 0; k < 4; k++) {
                            int x = i + d[k][0], y = j + d[k][1];
                            if (in(x, y, n, m) && g[x][y] == '.') {
                                if (!good(g, x, y, n, m) && goodAfter(g, x, y, i, j, n, m))
                                    add++;
                            }
                        }
                        maxAdd = max(maxAdd, add);
                    }
                }
            }
            
            cout << orig + maxAdd << endl;
            return 0;
        }
            
        
        
        
        • 0
          @ 2025-9-23 15:30:17
          #include <iostream>
          #include <vector>
          #include <string>
          using namespace std;
          inline bool in(int x, int y, int n, int m) {
              return x >= 0 && x < n && y >= 0 && y < m;
          }
          inline bool good(const vector<string>& g, int x, int y, int n, int m) {
              const int d[4][2] = {{-1,0},{1,0},{0,-1},{0,1}};
              for (int i = 0; i < 4; i++) {
                  int nx = x + d[i][0], ny = y + d[i][1];
                  if (in(nx, ny, n, m) && g[nx][ny] == '#')
                      return false;
              }
              return true;
          }
          inline bool goodAfter(const vector<string>& g, int x, int y, int cx, int cy, int n, int m) {
              const int d[4][2] = {{-1,0},{1,0},{0,-1},{0,1}};
              for (int i = 0; i < 4; i++) {
                  int nx = x + d[i][0], ny = y + d[i][1];
                  if ((nx == cx && ny == cy) || !in(nx, ny, n, m))
                      continue;
                  if (g[nx][ny] == '#')
                      return false;
              }
              return true;
          }
          
          int main() {
              int n, m;
              cin >> n >> m;
              vector<string> g(n);
              for (int i = 0; i < n; i++) cin >> g[i];
              int orig = 0;
              for (int i = 0; i < n; i++)
                  for (int j = 0; j < m; j++)
                      if (g[i][j] == '.' && good(g, i, j, n, m))
                          orig++;
              
              int maxAdd = 0;
              const int d[4][2] = {{-1,0},{1,0},{0,-1},{0,1}};
              for (int i = 0; i < n; i++) {
                  for (int j = 0; j < m; j++) {
                      if (g[i][j] == '#') {
                          int add = 0;
                          if (goodAfter(g, i, j, i, j, n, m)) add++;
                          for (int k = 0; k < 4; k++) {
                              int x = i + d[k][0], y = j + d[k][1];
                              if (in(x, y, n, m) && g[x][y] == '.') {
                                  if (!good(g, x, y, n, m) && goodAfter(g, x, y, i, j, n, m))
                                      add++;
                              }
                          }
                          maxAdd = max(maxAdd, add);
                      }
                  }
              }
              
              cout << orig + maxAdd << endl;
              return 0;
          }
              
          
          
          • 0
            @ 2025-9-22 20:38:05
            #include<bits/stdc++.h>
            #define ll long long
            using namespace std;
            const int N=1e3+10;
            const int INF=0x3f3f3f3f;
            inline int read(){ll x=0,f=1;char ch=getchar();while (ch<'0'||ch>'9'){if (ch=='-') f=-1;ch=getchar();}while (ch>='0'&&ch<='9'){x=x*10+ch-48;ch=getchar();}return x*f;}
            ll n,m,cnt,dx[4]={1,-1,0,0},dy[4]={0,0,-1,1},sum,ans;
            char a[N][N];
            bool check(ll x,ll y){
                for(int i=0;i<4;i++){
                    ll xx=x+dx[i],yy=y+dy[i];
                    if(xx>=1&&xx<=n&&yy>=1&&yy<=m&&a[xx][yy]=='#'){
                    	return 0;
            		}
                }
                return 1;
            }
            int main(){
            	//freopen(".in","r",stdin);
            	//freopen(".out","w",stdout);
                cin>>n>>m;
                for(int i=1;i<=n;i++){
                	for(int j=1;j<=m;j++){
                		cin>>a[i][j];
            		}
            	}
                for(int i=1;i<=n;i++){
                	for(int j=1;j<=m;j++){
                    	if(a[i][j]=='.'&&check(i,j)){
                    		cnt++;
            			}
            			else if(a[i][j]=='#'){
                            a[i][j]='.';
                            sum=0;
                            if(check(i,j)){
                            	sum++;
            				}
                            for(int k=0;k<4;k++){
                                ll xx=i+dx[k],yy=j+dy[k];
                                if(xx>=1&&xx<=n&&yy>=1&&yy<=m&&a[xx][yy]=='.'&&check(xx,yy)){
                                	sum++;
            					}
                            }
            				a[i][j]='#';
                        }
                        ans=max(ans,sum);
                	}
            	}
                cout<<ans+cnt;
            }
            
            
            • 1

            信息

            ID
            3314
            时间
            1000ms
            内存
            256MiB
            难度
            7
            标签
            递交数
            123
            已通过
            25
            上传者