2 条题解
-
0
#include using namespace std; int n, m, cx, cy; int main() { cin >> n >> m >> cx >> cy;
bool blocked[25][25] = {false}; blocked[cx][cy] = true; int dx[] = {2, 2, -2, -2, 1, 1, -1, -1}; int dy[] = {1, -1, 1, -1, 2, -2, 2, -2}; for (int i = 0; i < 8; ++i) { int nx = cx + dx[i]; int ny = cy + dy[i]; if (nx >= 0 && nx <= n && ny >= 0 && ny <= m) { blocked[nx][ny] = true; } } long long dp[25][25] = {0}; dp[0][0] = 1; for (int j = 1; j <= m; ++j) { if (!blocked[0][j]) { dp[0][j] = dp[0][j-1]; } } for (int i = 1; i <= n; ++i) { if (!blocked[i][0]) { dp[i][0] = dp[i-1][0]; } } for (int i = 1; i <= n; ++i) { for (int j = 1; j <= m; ++j) { if (!blocked[i][j]) { dp[i][j] = dp[i-1][j] + dp[i][j-1]; } } } cout << dp[n][m] << endl;return 0; }
//supermonkey 布置的7891978作业(MAN) -
-1
#include using namespace std; const int N = 105; char a[N][N]; int d[N][N],m,n; int x[4]={-1, 1, 0, 0}; int y[4]={0, 0, -1, 1}; int main() { cin >> n; for (int i=0;i<n;i++) for (int j=0;j<n;j++) cin >> a[i][j]; for (int i=0;i<n;i++) for (int j=0;j<n;j++) d[i][j]=-1; for (int i=0;i<n;i++) for (int j=0;j<n;j++) if (a[i][j]=='@') d[i][j]=1; cin>>m; for (int k = 1; k <= m; k++) { for (int i = 0; i < n; i++) { for (int j = 0; j < n; j++) { if (d[i][j] == k) { for (int l = 0; l < 4; l++) { int nx = i + x[l]; int ny = j + y[l]; if (nx >= 0 && nx < n && ny >= 0 && ny < n) { if (a[nx][ny] == '.' && d[nx][ny] == -1) d[nx][ny] = k + 1; } } } } } } int ans = 0; for (int i = 0; i < n; i++) for (int j = 0; j < n; j++) if (d[i][j] != -1 && d[i][j] <= m) ans++; cout << ans << endl; return 0; } //114514 //:) //包AC
- 1
信息
- ID
- 3516
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 9
- 标签
- (无)
- 递交数
- 12
- 已通过
- 4
- 上传者