题解 - 鸡兔问题

lhs LV 8 @ 2023-8-7 17:46:38

#include <iostream> 
using namespace std; 
int main(){ int n,m,x,y,z; cin>>n>>m; z=n/2; y=z-m; x=m-y; cout<<x<<" "<<y; }

-2
陈海斌 (阳光少年chen) LV 9 @ 2022-8-29 17:57:36

#include <iostream> using namespace std; int main(){ int n,m,x,y,z; cin>>n>>m; z=n/2; y=z-m; x=m-y; cout<<x<<" "<<y; } //数学版最简单的鸡兔同笼
- lhs @ 2023-8-7 17:46:53
  
  #include <iostream> using namespace std; int main(){ int n,m,x,y,z; cin>>n>>m; z=n/2; y=z-m; x=m-y; cout<<x<<" "<<y; }
-3
lililili LV 6 @ 2021-10-14 13:17:59

math=input().split() N=int(math[0]) M=int(math[1]) a=(N-(2M))//(4-2) print(M-((N-(2M))//(4-2)),a)
-3
lililili LV 6 @ 2021-10-14 13:16:59

math=input().split() N=int(math[0]) M=int(math[1]) a=(N-(2M))//(4-2) print(M-((N-(2M))//(4-2)),a)