11 条题解
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1Atterger(liyuwen) LV 5 @ 2023-5-12 17:39:49
#include <iostream> using namespace std; int main() { int n, shi, fen, miao; cin >> n; shi = n / 3600; fen = (n - shi * 3600) / 60; miao = (n - shi * 3600 - fen * 60); cout << shi << endl << fen << endl << miao; return 0; }
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02024-7-26 9:44:09@
using namespace std; int main() {#include <iostream>
int n,a,b,c; cin >>n; a=n/3600; b=n/60%60; c=n%60; cout <<a <<"\n" <<b <<"\n" <<c; return 0;
}
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02022-10-30 16:16:07@
#include <bits/stdc++.h> using namespace std; int main() { int s, m, h; cin >> s; m = s / 60; s = s % 60; h = m / 60; m = m % 60; cout << h << endl << m << endl << s; return 0; }
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-22023-4-27 13:39:23@
#include <bits/stdc++.h> using namespace std; int main() { int s, m, h; cin >> s; m = s / 60; s = s % 60; h = m / 60; m = m % 60; cout << h << endl << m << endl << s; return 0; }
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-32023-1-2 10:53:53@
using namespace std; int main(){ int h,m,s,t; cin>>t; h=t/3600; m=(t-h*3600)/60; s=t-h*3600-m*60; cout<<h<<endl<<m<<endl<<s; }
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-52023-2-11 10:44:51@
抄答案‽‽‽
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-72022-10-15 10:56:00@
#include<iostream>
using namespace std;
int main(){
int n,m,f,s;
cin>>n;
m=n%60;
f=n/60%60;
s=n/60/60%60;
cout<<s<<endl<<f<<endl<<m<<endl;
} -
-72022-8-13 19:03:43@
#include <iostream> #include <algorithm> #include <cstdio> #include <cstring> #include <string> #include <iomanip> #include <cmath> #include <queue> #include <map> #include <stack> #include <vector> using namespace std; #define long long LL const int N = 1e6+6; const int INF = 0x3f3f3f3f; int main(){ int n; cin >> n; cout << n / 3600 << endl; cout << (n - 3600 * (n / 3600)) / 60 << endl; cout << n % 60; return 0; }
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-72022-8-2 10:01:06@
#include <queue> #include <math.h> #include <stack> #include <stdio.h> #include <iostream> #include <vector> #include <iomanip> #include <string.h> #include <algorithm> using namespace std; #define LL long long const int N = 1e5 + 10; const int INF = 0x3f3f3f3f; int main() { int n; cin >> n; int a , b , c; a = n / 3600; cout << a <<endl; b = (n / 60)-(60 * a); cout << b <<endl; c = n-(60 * b)-(3600 * a); cout << c <<endl; }
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-82022-2-8 17:29:04@
#include <stdio.h> #include <iostream> using namespace std; int main() { int n; cin >> n; int a , b , c; a = n / 3600; cout << a <<endl; b = (n / 60)-(60 * a); cout << b <<endl; c = n-(60 * b)-(3600 * a); cout << c <<endl; }
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-102022-2-8 14:43:35@
#include<iostream> using namespace std; int main() { int a,b,c,d; cin>>a; b=a/3600; c=(a-((a/3600)*3600))/60; d=(a-((a/3600)3600)-c60)/1; cout<<b<<endl; cout<<c<<endl; cout<<d<<endl; }
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信息
- ID
- 836
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 4
- 标签
- 递交数
- 872
- 已通过
- 418
- 上传者