11 条题解

  • 1
    @ 2023-5-12 17:39:49
    #include <iostream>
    using namespace std;
    int main() 
    {
        int n, shi, fen, miao;
        cin >> n;
        shi = n / 3600;
        fen = (n - shi * 3600) / 60;
        miao = (n - shi * 3600 - fen * 60);
        cout << shi << endl << fen << endl << miao;
        return 0;
    }
    
    • 0
      @ 2024-7-26 9:44:09

      using namespace std; int main() {#include <iostream>

      int n,a,b,c;
      cin >>n;
      a=n/3600;
      b=n/60%60;
      c=n%60;
      cout <<a <<"\n" <<b <<"\n" <<c; 
      
      return 0;
      

      }

      • 0
        @ 2022-10-30 16:16:07
        #include <bits/stdc++.h>
        
        using namespace std;
        
        int main()
        {
            int s, m, h;
        
            cin >> s;
        
            m = s / 60;
            s = s % 60;
            h = m / 60;
            m = m % 60;
          
            cout << h << endl << m << endl << s;
        
            return 0;
        }
        
        • -2
          @ 2023-4-27 13:39:23
          #include <bits/stdc++.h>
          
          using namespace std;
          
          int main()
          {
              int s, m, h;
          
              cin >> s;
          
              m = s / 60;
              s = s % 60;
              h = m / 60;
              m = m % 60;
            
              cout << h << endl << m << endl << s;
          
              return 0;
          }
          
          • -3
            @ 2023-1-2 10:53:53
            using namespace std;
            int main(){
            	int h,m,s,t;
            	cin>>t;
            	h=t/3600;
            	m=(t-h*3600)/60;
            	s=t-h*3600-m*60;
            	cout<<h<<endl<<m<<endl<<s;
            }
            
            • -5
              @ 2023-2-11 10:44:51

              抄答案‽‽‽

              • -7
                @ 2022-10-15 10:56:00

                #include<iostream>
                using namespace std;
                int main(){
                int n,m,f,s;
                cin>>n;
                m=n%60;
                f=n/60%60;
                s=n/60/60%60;
                cout<<s<<endl<<f<<endl<<m<<endl;
                }

              • -7
                @ 2022-8-13 19:03:43
                #include <iostream>
                #include <algorithm>
                #include <cstdio>
                #include <cstring>
                #include <string>
                #include <iomanip>
                #include <cmath>
                #include <queue>
                #include <map>
                #include <stack>
                #include <vector>
                using namespace std;
                #define long long LL
                const int N = 1e6+6;
                const int INF = 0x3f3f3f3f;
                int main(){
                    int n;
                    cin >> n;
                    cout << n / 3600 << endl;
                    cout << (n -  3600 * (n / 3600)) / 60 << endl;
                    cout << n % 60;
                    return 0;
                }
                
                • -7
                  @ 2022-8-2 10:01:06
                  #include <queue> 
                  #include <math.h> 
                  #include <stack> 
                  #include <stdio.h>
                  #include <iostream>
                  #include <vector> 
                  #include <iomanip> 
                  #include <string.h> 
                  #include <algorithm>
                  using namespace std;
                  #define LL long long
                  const int N = 1e5 + 10; 
                  const int INF = 0x3f3f3f3f; 
                  int main()
                  {
                  	int n;
                  	cin >> n; 
                  	int a , b , c; a = n / 3600; 
                  	cout << a <<endl; 
                  	b = (n / 60)-(60 * a); 
                  	cout << b <<endl;
                  	c = n-(60 * b)-(3600 * a); 
                  	cout << c <<endl;	
                  }
                  
                  • -8
                    @ 2022-2-8 17:29:04

                    #include <stdio.h> #include <iostream> using namespace std; int main() { int n; cin >> n; int a , b , c; a = n / 3600; cout << a <<endl; b = (n / 60)-(60 * a); cout << b <<endl; c = n-(60 * b)-(3600 * a); cout << c <<endl; }

                    • -10
                      @ 2022-2-8 14:43:35

                      #include<iostream> using namespace std; int main() { int a,b,c,d; cin>>a; b=a/3600; c=(a-((a/3600)*3600))/60; d=(a-((a/3600)3600)-c60)/1; cout<<b<<endl; cout<<c<<endl; cout<<d<<endl; }

                      • 1

                      信息

                      ID
                      836
                      时间
                      1000ms
                      内存
                      128MiB
                      难度
                      4
                      标签
                      递交数
                      872
                      已通过
                      418
                      上传者