#include<iostream>
#include<iomanip>
#include<cmath>
using namespace std;
int n,a,ans;
int main()
{  
    cin >> n;
    for (int i = 1; i <= n; i++)
    {
        cin >> a;
        ans+=a/70;
        if(a%70!=0)
        ans+=1;
    }
    cout << ans/10<<"."<<ans%10;
}

#include<bits/stdc++.h>
using namespace std;
int main(){
    int in[1000]={0},i,n;
    float sum=0.0;
    cin >>n;
    for(i=0;i<n;i++)
        cin >> in[i];
    for(i=0;i<n;i++){
        while(in[i]>0){
            if(in[i]>70){
                in[i]-=70;
                sum+=0.1;
            }
            else{
                in[i]-=70;
                sum+=0.1;
            }  
        }
    }
    	printf("%.1f",sum);
}

#include <iostream>
#include <iomanip>
using namespace std;
int main(){
    int n,x,sum=0;
    cin>>n;
    for(int i=0;i<n;i++){
        cin>>x;
        while(x>0){
            x-=70;
            sum++;
        }
    }
    cout<<fixed<<setprecision(1)<<sum*0.1<<endl;
    return 0;
}

P903 短信计费

题面

一道水题，直接上代码罢

AC代码

#include<bits/stdc++.h>
using namespace std;
int n;
double cost(int n){//单条n字短信计费
	return ceil((double)n/70.0)*0.1;
}
int main(){
	double sum=0;
	cin>>n;
	for(int i=0;i<n;i++){
		int num;
		cin>>num;
		sum+=cost(num)；//计费累加
	}
	cout<<fixed<<setprecision(1)<<sum;//记得保留至小数点后1位
}

#include<iostream> #include<iomanip> #include<cstring> #include<string> #include<sstream> #include<cstdio> #include<cmath> #include<cstdlib> #include<queue> #include<vector> #include<algorithm> #include<stack> #include<fstream> #include<cstdlib> #include<ctime> #include<bits/stdc++.h> #define ll long long const int N=1e5+10; const int INF=0x3f3f3f3f; using namespace std; int main(){ int n,m,sum=0; cin>>n; for(int i=1;i<=n;i++){ cin>>m; sum+=m/70; if(m%70!=0){ sum+=1; } } cout<<setprecision(1)<<fixed<<sum*0.1; return 0; }

#include<iostream>

#include<iomanip>

#include<cmath>

using namespace std;

int n,a,ans;

int main()

{

cin >> n;

for (int i = 1; i <= n; i++)

{

    cin >> a;

    ans+=a/70;

    if(a%70!=0)

    ans+=1;

}

cout << ans/10<<"."<<ans%10;

}

#include<cstdio> using namespace std; int n,a,b,c; double s; int main() { scanf("%d",&n); for(int i=0;i<n;i++) { scanf("%d",&a); if(a%70==0) s+=a/70; else s+=a/70+1; } printf("%0.1lf",s/10); return 0; }

#include <stdio.h> #include <iostream> #include <math.h> using namespace std; int main() { int n; cin >> n; int sum = 0; for(int i = 0 ;i < n ; i++) { int x; cin >> x; sum += x/70; if(x%70 != 0) { sum++ } } cout << sum/10 << "." << sum%10 << endl; }