7 条题解

  • 4
    @ 2021-10-25 17:39:20
    #include <math.h>
    #include <stdio.h>
    #include <iostream>
    #include <string.h>
    #include <algorithm>
    #include <queue>
    using namespace std;
    char a[155][155];
    struct node
    {
        int x,y,step;
    };
    int n , m;
    int dx[] = {1,1,-1,-1,2,2,-2,-2}; 
    int dy[] = {2,-2,2,-2,1,-1,1,-1};
    int bfs(int x , int y)
    {
        queue<node> p;
        p.push( (node){x,y,0} );
        a[x][y] = '*';
        while(!p.empty())
        {
            node t = p.front();
            p.pop();
            for(int i = 0 ; i < 8 ;i++)
            {
                x = dx[i] + t.x;
                y = dy[i] + t.y;
                if(x < 0 || y < 0 || x>= n || y >= m || a[x][y]=='*')
                    continue;
                if(a[x][y] == 'H')
                    return t.step + 1;
                a[x][y] = '*';
                p.push((node){x,y,t.step + 1});
            } 
        }
        return -1;
    }
    int main()
    {
        cin >> m >> n;
        int sx,sy;
        for(int i = 0 ; i < n ; i++)
        {
            cin >> a[i];
            for(int j = 0 ; j < m ; j++)
            {
                if(a[i][j] == 'K')
                    sx = i , sy = j;
            }
        }
        cout << bfs(sx,sy);
        return 0;
    }
    
    • 0
      @ 2023-1-6 12:29:35
      #include<bits/stdc++.h>
      using namespace std;
      int n,m,sx,sy,ex,ey;
      char ch;
      int a[155][155];
      bool qp[155][155];
      struct id
      {
      	int x,y,s;
      };
      queue<id>q;
      int xx[8]={1,1,-1,-1,2,2,-2,-2};
      int yy[8]={2,-2,2,-2,1,-1,1,-1};
      int main()
      {
      	memset(qp,false,sizeof(qp));
      	cin>>n>>m;
      	for(int i=1;i<=m;i++)
      	{
      		for(int j=1;j<=n;j++)
      		{
      			cin>>ch;
      			if(ch=='*')continue;
      			qp[i][j]=true;
      			if(ch=='K')sx=i,sy=j;
      			if(ch=='H')ex=i,ey=j;
      		}
      	}
      	q.push(id{sx,sy,0});
      	qp[sx][sy]=false;
      	while(!q.empty())
      	{
      		id t=q.front();
      		q.pop();
      		for(int i=0;i<8;i++)
      		{
      			int nx=t.x+xx[i];
      			int ny=t.y+yy[i];
      			if(qp[nx][ny])
      			{
      				if(nx==ex&&ny==ey)
      				{
      					cout<<t.s+1;
      					return 0;
      				}
      				q.push(id{nx,ny,t.s+1});
      				qp[nx][ny]=false;
      			}
      		}
      	}
      }
      
      • 0
        #include<bits/stdc++.h>
        using namespace std;
        const int N = 155;
        int n, m;
        char str[N][N];
        int dis[N][N];
        int dir[8][2] = {{1, 2}, {2, 1}, {2, -1,}, {-1, 2}, {-2, 1}, {1, -2}, {-2, -1}, {-1, -2}};
        queue<pair<int, int> >q;
        bool cp(int x, int y)
        {
        	if(x < 1 || y < 1 || x > n || y > m || str[x][y] == '*' || dis[x][y] != -1) return false;
        	else return true;
        }
        int bfs(int ex, int ey)
        {
        	while(q.size())
        	{
        		pair<int,int>ad;
        		ad= q.front();
        		q.pop();
        		if(ad.first == ex &&ad.second == ey)
        			return dis[ad.first][ad.second];
        		for(int i = 0; i < 8; i++)
        		{
        			int xx = dir[i][0] +ad.first;
        			int yy = dir[i][1] +ad.second;
        			if(cp(xx, yy))
        			{
        				dis[xx][yy] = dis[ad.first][ad.second] + 1;
        				q.push(make_pair(xx, yy));
        			}
        		}
        	}
        }
        
        int main()
        {
        	int ex, ey; 
        	ios::sync_with_stdio(false);
        	memset(dis, -1, sizeof(dis));
        	cin >> m >> n;
        	for(int i=1;i<=n;i++)
        	{
        		for(int j=1;j<=m;j++)
        		{
        			cin>>str[i][j];
        			if(str[i][j]=='K')
        			{
        				q.push(make_pair(i,j));
        				dis[i][j]=0;
        			}
        			if(str[i][j]=='H')
        			{
        				ex=i;
        				ey=j;
        			}
        		}
        	}
        	cout<<bfs(ex,ey);
        	return 0;
        }
        
        • -2

          #include <math.h> #include <stdio.h> #include <iostream> #include <string.h> #include <algorithm> #include <queue> using namespace std; char a[155][155]; struct node { int x,y,step; }; int n , m; int dx[] = {1,1,-1,-1,2,2,-2,-2}; int dy[] = {2,-2,2,-2,1,-1,1,-1}; int bfs(int x , int y) { queue<node> p; p.push( (node){x,y,0} ); a[x][y] = ''; while(!p.empty()) { node t = p.front(); p.pop(); for(int i = 0 ; i < 8 ;i++) { x = dx[i] + t.x; y = dy[i] + t.y; if(x < 0 || y < 0 || x>= n || y >= m || a[x][y]=='') continue; if(a[x][y] == 'H') return t.step + 1; a[x][y] = '*'; p.push((node){x,y,t.step + 1}); } } return -1; } int main() { cin >> m >> n; int sx,sy; for(int i = 0 ; i < n ; i++) { cin >> a[i]; for(int j = 0 ; j < m ; j++) { if(a[i][j] == 'K') sx = i , sy = j; } } cout << bfs(sx,sy); return 0; }

          • -2
            @ 2022-2-11 16:38:41
            #include <bits/stdc++.h>
            using namespace std;
            const int MAXN = 1e3 + 10;
            int n, m, startx, starty, endx, endy, a[MAXN][MAXN], ans = 0;
            int dir[8][2] = {{-2,-1},{2,1},{-1,2},{1,-2},{-2,1},{2,-1},{1,2},{-1,-2}};
            int front = 0,rear = 0;
            queue<int> qx, qy;
            void bfs(int x,int y){
            	qx.push(x);
            	qy.push(y);
            	a[x][y] = 1;
            	while(!qx.empty()){
            		for(int i = 0;i <= 7; i++){
            			int tx = qx.front() + dir[i][0];
            			int ty = qy.front() + dir[i][1];
            			if(tx == endx && ty == endy){
            				ans++;
            				return ;
            			}
            			if(tx > n || ty > m || ty <0 || tx < 0 || a[tx][ty] == 1){
            				continue;
            			}
            			qx.push(tx);
            			qy.push(ty);
            			rear++;
            			a[tx][ty] = 1;
            		}
            		
            		qx.pop();
            		qy.pop();
            		if(front == 0 && rear != 0){
            			front = rear;
            			rear = 0;
            			ans++;
            		}
            		front--;
            	}
            }
            int main(){
            	string line;
            	cin >> m >> n;
            	for(int i = 1;i <= n; i++){
            		cin >> line;
            		for(int j = 0;j < line.size(); j++){
            			if(line[j] == '.')a[i][j + 1] = 0;
            			else if(line[j] == '*')a[i][j + 1] = 1;
            			else if(line[j] == 'K'){
            				a[i][j + 1] = 1;
            				startx = i,starty = j + 1;
            			}
            			else if(line[j] == 'H'){
            				a[i][j + 1] = 0;
            				endx = i,endy = j + 1;
            			}
            		}
            	}
            	bfs(startx, starty);
            	cout << ans << endl;
            }
            
            
            • -2
              @ 2021-10-25 18:01:17

              // #include <math.h> #include <stdio.h> #include <iostream> #include <string.h> #include <algorithm> #include <queue> using namespace std; char a[155][155]; struct node { int x,y,step; }; int n , m; int dx[] = {1,1,-1,-1,2,2,-2,-2}; int dy[] = {2,-2,2,-2,1,-1,1,-1}; int bfs(int x , int y) { queue<node> p; p.push( (node){x,y,0} ); a[x][y] = ''; while(!p.empty()) { node t = p.front(); p.pop(); for(int i = 0 ; i < 8 ;i++) { x = dx[i] + t.x; y = dy[i] + t.y; if(x < 0 || y < 0 || x>= n || y >= m || a[x][y]=='') continue; if(a[x][y] == 'H') return t.step + 1; a[x][y] = ''; p.push((node){x,y,t.step + 1}); } } return -1; } int main() { cin >> m >> n; int sx,sy; for(int i = 0 ; i < n ; i++) { cin >> a[i]; for(int j = 0 ; j < m ; j++) { if(a[i][j] == 'K') sx = i , sy = j; } } cout << bfs(sx,sy); return 0; }

              • -2
                @ 2021-10-25 18:00:33

                #include <math.h> #include <stdio.h> #include <iostream> #include <string.h> #include <algorithm> #include <queue> using namespace std; char a[155][155]; struct node { int x,y,step; }; int n , m; int dx[] = {1,1,-1,-1,2,2,-2,-2}; int dy[] = {2,-2,2,-2,1,-1,1,-1}; int bfs(int x , int y) { queue<node> p; p.push( (node){x,y,0} ); a[x][y] = ''; while(!p.empty()) { node t = p.front(); p.pop(); for(int i = 0 ; i < 8 ;i++) { x = dx[i] + t.x; y = dy[i] + t.y; if(x < 0 || y < 0 || x>= n || y >= m || a[x][y]=='') continue; if(a[x][y] == 'H') return t.step + 1; a[x][y] = '*'; p.push((node){x,y,t.step + 1}); } } return -1; } int main() { cin >> m >> n; int sx,sy; for(int i = 0 ; i < n ; i++) { cin >> a[i]; for(int j = 0 ; j < m ; j++) { if(a[i][j] == 'K') sx = i , sy = j; } } cout << bfs(sx,sy); return 0; }

                • 1

                信息

                ID
                99
                时间
                1000ms
                内存
                128MiB
                难度
                5
                标签
                递交数
                362
                已通过
                130
                上传者