6 条题解

  • 1
    #include <bits/stdc++.h>
    using namespace std;
    const int N=1e4+10;
    const int INF=0x3f3f3f3f;
    int a[N];
    double sum;
    int ans,n;
    int main()
    {
    	cin>>n;
    	for(int i=1;i<=n;i++)
    	{
    		cin>>a[i];
    		sum+=a[i];
    	}
    	sum/=n;
    	for(int i=1;i<=n;i++)
    	{
    		if(a[i]<sum)
    		{
    			ans++;
    		}
    	}
    	cout<<ans;
    	return 0;
    }
    
    
    • 1
      @ 2022-8-26 18:05:40
      /*****************************************
      备注:
      ******************************************/
      #include <queue>
      #include <math.h>
      #include <stack>
      #include <stdio.h>
      #include <iostream>
      #include <vector>
      #include <iomanip>
      #include <string.h>
      #include <algorithm>
      using namespace std;
      #define LL long long
      const int N = 1e5 + 10;
      const int INF = 0x3f3f3f3f;
      int main()
      {
      	double n;
      	double a[N];
      	cin >> n;
      	double sum = 0;
      	for(int i = 0 ; i < n ; i++ )
      	{
      		cin >> a[i];
      		sum += a[i];
      	}
      	double s = sum / n;
      	int cnt = 0;
      	for(int i = 0 ; i < n ; i++)
      	{
      		if(a[i] < s)
      			cnt ++;
      	}
      	cout << cnt << endl;
      	return 0;
      }
      
      • 0
        @ 2024-2-17 18:56:51

        #include<iostream> #include<iomanip> #include<algorithm> #include<cstring> #include<bits/stdc++.h>//memset(a,0x3f,sizeof(a)); using namespace std;//cout<<fixed<<setprecision() int a[10005]; int main() { int s,t=0; double y=0; cin>>s; for(int i=0;i<=s-1;i++) { cin>>a[i]; } for(int i=0;i<=s-1;i++) { y+=a[i]; } y/=s; for(int i=0;i<=s-1;i++) { if(y>a[i]) { t++; } } cout<<t; return 0; }

        • 0
          @ 2023-4-3 13:53:13
          #include<iostream>
          //#include<iomanip>
          //#include<math.h>
          using namespace std;
          const int N = 1e5 + 10;//1*10^5 + 10
          const int INF = 0x3f3f3f3f;
          double n , a[N] , sum , avg , ans;
          
          int main(){
              cin >> n ;
              
              for(int i = 1;i <= n;i++){
                  cin >> a[i];
                  sum += a[i];
                  }
                  
          	avg = sum / n; 
          	
          	for(int i = 1;i <= n;i++){
                  if(a[i] < avg){
                  	ans ++;
          		}
                  }  
                  
              //if(i == 1){
              //    pass
              //}else{
              //    pass
              //}
          
              cout << ans ;
              return 0;
          }
          
          • 0
            @ 2023-4-2 21:45:16
            using namespace std;
            const int N = 1e5 + 10;
            const int INF = 0x3f3f3f3f;
            int main(){
            	double n;
            	double a[N];
            	cin >> n;
            	double sum = 0;
            	for(int i = 0 ; i < n ; i++ ){
            		cin >> a[i];
            		sum += a[i];
            	}
            	double s = sum / n;
            	int cnt = 0;
            	for(int i = 0 ; i < n ; i++){
            		if(a[i] < s)
            			cnt ++;
            	}
            	cout << cnt << endl;
            	return 0;
            }
            
            • -1
              @ 2023-1-30 16:46:56

              #include <queue>

              #include <iostream>

              #include <iomanip>

              #include <cmath>

              #include <cstring>

              #include <string>

              #include <algorithm>

              #include <vector>

              using namespace std;

              int main()

              {

              double s=0,x;

              int b=0,n;

              cin >> n;

              double a[n+1];

              for(int i=1;i<=n;i++)

              {

              cin >> a[i];

              s += a[i];

              }

              x = s / n;

              for(int i=n;i>=1;i--)

              {

              if(a[i] < x)b++;

              }

              cout << b;

              return 0;

              }

              • 1

              信息

              ID
              1018
              时间
              1000ms
              内存
              256MiB
              难度
              5
              标签
              递交数
              353
              已通过
              136
              上传者