10 条题解
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2
#include <queue> #include <math.h> #include <stack> #include <stdio.h> #include <iostream> #include <vector> #include <iomanip> #include <string.h> #include <algorithm> using namespace std; #define LL long long const int N = 1e6 + 10; const int INF = 0x3f3f3f3f; int a[110][110], n, m; int main() { cin >> n >> m; for(int i = 1; i <= n; i++) { for(int j = 1; j <= m; j++) { cin >> a[i][j]; } } //其实不用真的转90° for(int i = 1; i <= m; i++)//仔细想想这三句 { for(int j = n; j >= 1; j--)//为什么一个加一个减 { cout << a[j][i] << " ";//为什么要反着输出 } puts(""); } return 0; } -
1
ts2024stu008 LV 10 @ 2025-1-24 13:08:34
#include <bits/stdc++,h> using namespace std; const int N=1e3+10; const int INF=0x3f3f3f3f; int n,m,a[N][N]; int main() { cin >> n >> m; for(int i=1;i<=n;i++) { for(int j=1;j<=m;j++) { cin >> a[i][j]; } } for(int j=1;j<=m;j++) { for(int i=n;i>=1;i--) { cout << a[i][j] << " "; } cout << endl; } return 0; } //ts2024stu008~~~~~有标志认证，属三无产品，请大家放心食用
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0
cuiyangyang1
LV 7
@ 2024-10-25 18:20:00
6
#include <bits/stdc++.h> using namespace std; int a[105][105]; int n,m; int main(){ cin>>n>>m; for(int i=1;i<=n;i++){ for(int j=1;j<=m;j++){ cin>>a[i][j]; } } for(int j=1;j<=m;j++){ for(int i=n;i>=1;i--){ cout<<a[i][j]<<" "; } cout<<endl; } return 0; } -
0
Lawrence劳伦斯 LV 10 @ 2023-9-17 18:52:35
看似难实则简单
#include <iostream> #include <bits/stdc++.h> using namespace std; const int N=1e4+10; const int INF=0x3f3f3f3f; int n,m,a[N][N]; int main() { cin>>n>>m; for(int i=1;i<=n;i++) { for(int j=1;j<=m;j++) { cin>>a[i][j]; } } for(int j=1;j<=m;j++) { for(int i=n;i>=1;i--) { cout<<a[i][j]<<" "; } cout<<endl; } } -
0
//@#@#@#@#@#@#@# #include<iostream> #include<cstdio> #include<string> #include<bits/stdc++.h> #define LL long long using namespace std; const int INF=0x3f3f3f3f; const int N=2e5+10; int a[20000][20000],b,c; int main(){ cin>>b>>c; for(int i=1;i<=b;i++){ for(int j=1;j<=c;j++){ cin>>a[i][j]; } } for(int i=1;i<=c;i++){ for(int j=b;j>=1;j--){ cout<<a[j][i]<<" "; } cout<<endl; } } -
0
#include using namespace std; const int N=1e2+10; int a[N][N],n,m; int main() { cin >> n >> m; for(int i = 1; i <= n; i++) { for(int j = 1; j <= m; j++) { cin >> a[i][j]; } } for(int i = 1; i <= m; i++) { for(int j = n; j >= 1; j--) { cout << a[j][i] <<" "; } cout<<endl; } return 0; }
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-1
liangzhekai LV 8 @ 2024-10-25 19:51:58
#include <iostream> #include <bits/stdc++.h> using namespace std; const int N=1e4+10; const int INF=0x3f3f3f3f; int n,m,a[N][N]; int main() { cin>>n>>m; for(int i=1;i<=n;i++) { for(int j=1;j<=m;j++) { cin>>a[i][j]; } } for(int j=1;j<=m;j++) { for(int i=n;i>=1;i--) { cout<<a[i][j]<<" "; } cout<<endl; } } -
-1
#include<bits/stdc++.h> using namespace std; const int N=1e2+10; const int INF=0x3f3f3f3f; int n,m,a[N][N]; int main(){ cin>>n>>m; for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) cin>>a[i][j];
for(int i=1;i<=m;i++){ for(int j=n;j>=1;j--){ cout<<a[j][i]<<" "; } cout<<endl; } return 0;}
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-2
#include #include <math.h> #include #include <stdio.h> #include #include #include #include <string.h> #include using namespace std; const int N = 1e6 + 10; const int INF = 0x3f3f3f3f; int a[110][110], n, m; int main() { cin >> n >> m; for(int i = 1; i <= n; i++) { for(int j = 1; j <= m; j++) { cin >> a[i][j]; } }
for(int i = 1; i <= m; i++) { for(int j = n; j >= 1; j--) { cout << a[j][i] << " "; } cout << endl; } return 0;}
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-3
kanghaoxuan LV 9 @ 2023-4-12 18:59:26
#include <iostream> using namespace std; #define LL long long const int N = 1e6 + 10; const int INF = 0x3f3f3f3f; int a[110][110], n, m; int main() { cin >> n >> m; for(int i = 1; i <= n; i++) { for(int j = 1; j <= m; j++) { cin >> a[i][j]; } } //其实不用真的转90° for(int i = 1; i <= m; i++)//仔细想想这三句 { for(int j = n; j >= 1; j--)//为什么一个加一个减 { cout << a[j][i] << " ";//为什么要反着输出 } puts(""); } return 0; }
许栋轶
LV 10
@ 2022-11-28 9:56:53
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