9 条题解

  • 1

    看似难实则简单

    #include <iostream>
    #include <bits/stdc++.h>
    using namespace std;
    const int N=1e4+10;
    const int INF=0x3f3f3f3f;
    int n,m,a[N][N];
    int main()
    {
    	cin>>n>>m;
    	for(int i=1;i<=n;i++)
    	{
    		for(int j=1;j<=m;j++)
    		{
    			cin>>a[i][j];
    		}
    	}
    	for(int j=1;j<=m;j++)
    	{
    		for(int i=n;i>=1;i--)
    	    {
    		    cout<<a[i][j]<<" ";
    		}
    		cout<<endl;
    	}
    }
    
    • 1
      @ 2023-9-5 21:36:20
      //@#@#@#@#@#@#@#
      #include<iostream>
      #include<cstdio>
      #include<string>
      #include<bits/stdc++.h>
      #define LL long long
      using namespace std;
      const int INF=0x3f3f3f3f;
      const int N=2e5+10;
      int a[20000][20000],b,c;
      int main(){
      	cin>>b>>c;
      	for(int i=1;i<=b;i++){
      		for(int j=1;j<=c;j++){
      			cin>>a[i][j];
      		}
      	}
      	for(int i=1;i<=c;i++){
      		for(int j=b;j>=1;j--){
      			cout<<a[j][i]<<" ";
      		}
      		cout<<endl;
      	}
      }
      
      • 0
        #include <iostream>
        #include <bits/stdc++.h>
        using namespace std;
        const int N=1e4+10;
        const int INF=0x3f3f3f3f;
        int n,m,a[N][N];
        int main()
        {
        	cin>>n>>m;
        	for(int i=1;i<=n;i++)
        	{
        		for(int j=1;j<=m;j++)
        		{
        			cin>>a[i][j];
        		}
        	}
        	for(int j=1;j<=m;j++)
        	{
        		for(int i=n;i>=1;i--)
        	    {
        		    cout<<a[i][j]<<" ";
        		}
        		cout<<endl;
        	}
        }
        
        • 0
          @ 2024-10-25 18:20:00

          6

          #include <bits/stdc++.h>
          using namespace std;
          int a[105][105];
          int n,m;
          int main(){
          	cin>>n>>m;
          	for(int i=1;i<=n;i++){
          		for(int j=1;j<=m;j++){
          			cin>>a[i][j];
          		}
          	}
          	for(int j=1;j<=m;j++){
          		for(int i=n;i>=1;i--){
          			cout<<a[i][j]<<" ";
          		}
          		cout<<endl;
          	}
          	return 0;
          }
          
          • 0
            @ 2023-5-10 20:28:58

            #include <iostream> using namespace std; const int N=1e2+10; int a[N][N],n,m; int main() { cin >> n >> m; for(int i = 1; i <= n; i++) { for(int j = 1; j <= m; j++) { cin >> a[i][j]; } } for(int i = 1; i <= m; i++) { for(int j = n; j >= 1; j--) { cout << a[j][i] <<" "; } cout<<endl; } return 0; }

            • 0
              @ 2022-11-28 9:56:53
              #include <queue>
              #include <math.h>
              #include <stack>
              #include <stdio.h>
              #include <iostream>
              #include <vector>
              #include <iomanip>
              #include <string.h>
              #include <algorithm>
              using namespace std;
              #define LL long long
              const int N = 1e6 + 10;
              const int INF = 0x3f3f3f3f;
              int a[110][110], n, m;
              int main()
              {
                  cin >> n >> m;
              	for(int i = 1; i <= n; i++)
                  {
                      for(int j = 1; j <= m; j++)
                      {
                          cin >> a[i][j];
                      }
                  }
                  //其实不用真的转90°
                  for(int i = 1; i <= m; i++)//仔细想想这三句
                  {
                      for(int j = n; j >= 1; j--)//为什么一个加一个减
                      {
                          cout << a[j][i] << " ";//为什么要反着输出
                      }
                      puts("");
                  }
              	return 0;
              }
              
              • -1
                @ 2023-5-13 14:43:11
                
                

                #include <queue> #include <math.h> #include <stack> #include <stdio.h> #include <iostream> #include <vector> #include <iomanip> #include <string.h> #include <algorithm> using namespace std; const int N = 1e6 + 10; const int INF = 0x3f3f3f3f; int a[110][110], n, m; int main() { cin >> n >> m; for(int i = 1; i <= n; i++) { for(int j = 1; j <= m; j++) { cin >> a[i][j]; } }

                for(int i = 1; i <= m; i++)
                {
                    for(int j = n; j >= 1; j--)
                    {
                        cout << a[j][i] << " ";
                    }
                    cout << endl;
                }
                return 0;
                

                }

                
                
                • -1
                  @ 2023-5-10 20:28:23

                  #include<bits/stdc++.h> using namespace std; const int N=1e2+10; const int INF=0x3f3f3f3f; int n,m,a[N][N]; int main(){ cin>>n>>m; for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) cin>>a[i][j];

                  for(int i=1;i<=m;i++){
                  	for(int j=n;j>=1;j--){
                  		cout<<a[j][i]<<" ";
                  	}
                  	cout<<endl;
                  }
                  
                  return 0;
                  

                  }

                  • -2
                    @ 2023-4-12 18:59:26
                    #include <iostream>
                    using namespace std;
                    #define LL long long
                    const int N = 1e6 + 10;
                    const int INF = 0x3f3f3f3f;
                    int a[110][110], n, m;
                    int main()
                    {
                        cin >> n >> m;
                    	for(int i = 1; i <= n; i++)
                        {
                            for(int j = 1; j <= m; j++)
                            {
                                cin >> a[i][j];
                            }
                        }
                        //其实不用真的转90°
                        for(int i = 1; i <= m; i++)//仔细想想这三句
                        {
                            for(int j = n; j >= 1; j--)//为什么一个加一个减
                            {
                                cout << a[j][i] << " ";//为什么要反着输出
                            }
                            puts("");
                        }
                    	return 0;
                    }
                    
                    • 1

                    信息

                    ID
                    1071
                    时间
                    1000ms
                    内存
                    128MiB
                    难度
                    5
                    标签
                    递交数
                    595
                    已通过
                    206
                    上传者