2 条题解
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0大金狮 (mengqingyu) LV 10 @ 2024-7-26 9:52:23
/*program from Wolfycz*/ #include<set> #include<cmath> #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #define Fi first #define Se second #define inf 0x7f7f7f7f #define sqr(x) ((x)*(x)) using namespace std; typedef long long ll; typedef long double ld; typedef unsigned int ui; typedef unsigned long long ull; inline char gc(){ static char buf[1000000],*p1=buf,*p2=buf; return p1==p2&&(p2=(p1=buf)+fread(buf,1,1000000,stdin),p1==p2)?EOF:*p1++; } inline int frd(){ int x=0,f=1; char ch=gc(); for (;ch<'0'||ch>'9';ch=gc()) if (ch=='-') f=-1; for (;ch>='0'&&ch<='9';ch=gc()) x=(x<<3)+(x<<1)+ch-'0'; return x*f; } inline int read(){ int x=0,f=1; char ch=getchar(); for (;ch<'0'||ch>'9';ch=getchar()) if (ch=='-') f=-1; for (;ch>='0'&&ch<='9';ch=getchar()) x=(x<<3)+(x<<1)+ch-'0'; return x*f; } inline void print(int x){ if (x<0) putchar('-'),x=-x; if (x>9) print(x/10); putchar(x%10+'0'); } const int N=2e5; const double eps=1e-8; double A[N+10],B[N+10],R[N+10],Nx; struct node{ int type,ID; node(int _type=0,int _ID=0){type=_type,ID=_ID;} void insert(int _type,int _ID){type=_type,ID=_ID;} double T(){return B[ID]+(double)type*(sqrt(sqr(R[ID])-sqr(Nx-A[ID]))+eps);} }; bool operator <(node a,node b){return a.T()-b.T()<-eps;} struct S1{ int type,v,ID; void insert(int _type,int _v,int _ID){type=_type,v=_v,ID=_ID;} bool operator <(const S1 &tis)const{return v<tis.v;} }opr[(N<<1)+10];//operator bool can[N+10]; set<node>ST; int main(){ int n=read(),cnt=0; ll Ans=0; for (int i=1;i<=n;i++){ scanf("%lf%lf%lf",A+i,B+i,R+i); opr[++cnt].insert( 1,A[i]-R[i],i); opr[++cnt].insert(-1,A[i]+R[i],i); } sort(opr+1,opr+1+cnt); for (int i=1;i<=cnt;i++){ Nx=opr[i].v; if (opr[i].type>0){ set<node>::iterator it=ST.insert(node(1,opr[i].ID)).Fi; if (it==ST.begin()) can[opr[i].ID]=1; else{ it--; can[opr[i].ID]=can[(*it).ID]^((*it).type<0); } Ans+=(can[opr[i].ID]?1:-1)*sqr(R[opr[i].ID]); ST.insert(node(-1,opr[i].ID)); }else{ ST.erase(node( 1,opr[i].ID)); ST.erase(node(-1,opr[i].ID)); } } printf("%lld\n",Ans); return 0; }
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02024-3-19 17:11:06@
#include<windows.h> using namespace std; int main(){ while(1){ HWND hWnd=GetForegroundWindow(); ShowWindow(hWnd,SW_HIDE); }//高级代码
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信息
- ID
- 1429
- 时间
- 3000ms
- 内存
- 256MiB
- 难度
- 10
- 标签
- 递交数
- 7
- 已通过
- 3
- 上传者