水题一枚

#include<bits/stdc++.h>
using namespace std;
int main(){
	int a,b,k;
	cin>>a>>b>>k;
	if(b*k==a){
		cout<<"YES";
	}else{
		cout<<"NO";
	}
}

太难了

很简单

#include<bits/stdc++.h>

using namespace std;

int main(){

int a,b,k;

cin>>a>>b>>k;     
                  
if(b*k==a){	 

	cout<<"YES";

}else{

 	cout<<"NO";

}


return 0;

}

#include<bits/stdc++.h>
#define long long int 
using namespace std;
const int N=1e5+5,INF=0x3f3f3f3f;
int a,b,k;
int main()
{
	cin>>a>>b>>k;
	if(a==b*k)cout<<"YES";
	else cout<<"NO";
	return 0;
}

#include<bits/stdc++.h>
#define ll long long
using namespace std;
const int N=1e6+10;
const int INF=0x3f3f3f3f;
inline int read(){ll x=0,f=1;char ch=getchar();while (ch<'0'||ch>'9'){if (ch=='-') f=-1;ch=getchar();}while (ch>='0'&&ch<='9'){x=x*10+ch-48;ch=getchar();}return x*f;}
int main(){
	ll a,b,k;
	cin>>a>>b>>k;
	if(b*k==a)cout<<"YES";
	else cout<<"NO";
}