1 条题解
-
0大金狮 (mengqingyu) LV 10 @ 2024-10-2 19:56:46
#include <bits/stdc++.h> using namespace std; typedef long long LL; #define INF 2000000000 #define FF first #define SS second int n, m; vector<pair<LL, LL>> intervals; bool ok(LL d) { LL prev = -1LL * INF * INF; int cnt = 0; for (auto& i : intervals) { while (max(prev + d, i.FF) <= i.SS) { prev = max(prev + d, i.FF); cnt++; if (cnt >= n) break; } if (cnt >= n) break; } return (cnt >= n); } int main() { cin >> n >> m; intervals.resize(m); for (int i = 0; i < m; ++i) cin >> intervals[i].FF >> intervals[i].SS; sort(intervals.begin(), intervals.end()); LL lo = 0;// LL hi = 1LL * INF * INF; LL res = -1; while (lo <= hi) { LL mid = (lo + hi) / 2; if (ok(mid)) { res = mid; lo = mid + 1; } else { hi = mid - 1; } } cout << res << "\n"; return 0 }
- 1
信息
- ID
- 3192
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 8
- 标签
- (无)
- 递交数
- 180
- 已通过
- 27
- 上传者