2 条题解
-
1
简简单单
AC code
#include<queue> #include<math.h> #include<stdio.h> #include<iostream> #include<vector> #include<iomanip> #include<string.h> #include<algorithm> #include<cmath> #include<cstdio> #include<utility> #include<cstring> #include<stack> #include<fstream> #include<string> using namespace std; #define LL long long const int INF = 0x3f3f3f3f; const int N = 12010; const int M = 2010; int n , m; int v[N] , w[N]; int f[M]; int main() { cin >> n >> m; int c = 0; for ( int i = 1 ; i <= n ; i++ ) { int a , b , s; cin >> a >> b >> s; int k = 1; while ( k <= s ) { c++; v[c] = a * k; w[c] = b * k; s -= k; k *= 2; } if ( s > 0 ) { c++; v[c] = s * a; w[c] = b * s; } } n = c; for ( int i = 1 ; i <= n ; i++ ) { for ( int j = m ; j >= v[i] ; j-- ) { f[j] = max( f[j] , f[ j - v[i] ] + w[i] ); } } cout << f[m]; return 0; }
😂😂😂
-
0
#include<iostream> using namespace std; const int N=12010, M=2010; int n,m; int v[N],w[N]; int f[M]; int main() { cin>>n>>m; int c=0; for(int i=1;i<=n;i++) { int a,b,s; cin>>a>>b>>s; int k=1; while(k<=s) { c++; v[c]=a*k; w[c]=b*k; s-=k; k*=2; } if(s>0) { c++; v[c]=s*a; w[c]=b*s; } } n=c; for(int i=1;i<=n;i++) { for(int j=m;j>=v[i];j--) { f[j]=max(f[j],f[j-v[i]]+w[i]); } } cout<<f[m]<<endl; return 0; } ``` `
- 1
信息
- ID
- 3273
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 4
- 标签
- 递交数
- 52
- 已通过
- 26
- 上传者