8 条题解
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1韦卓奇 (weizhuoqi) LV 6 @ 2024-11-24 12:08:02
#include<bits/stdc++.h> using namespace std; struct student{ int id,yw,sx,yy,sum; }a[505]; int cmp(student a,student b){ if(a.sum>b.sum) return 1; else if(a.sumb.sum&&a.yw>b.yw) return 1; else if(a.ywb.yw&&a.sum==b.sum&&a.id<b.id) return 1; else return 0; } int main(){ int n; cin>>n; for(int i=1;i<=n;i++){ cin>>a[i].yw>>a[i].sx>>a[i].yy; a[i].sum=a[i].yw+a[i].sx+a[i].yy; a[i].id=i; } sort(a+1,a+n+1,cmp); for(int i=1;i<=5;i++)cout<<a[i].id<<" "<<a[i].sum<<endl; return 0; }
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12024-11-23 18:36:33@
#include<bits/stdc++.h> using namespace std; struct student{ int id,yw,sx,yy,sum; }a[505]; int cmp (student a,student b){ if(a.sum>b.sum) return 1; else if(a.sum==b.sum&&a.yw>b.yw) return 1; else if(a.yw==b.yw&&a.sum==b.sum&&a.id<b.id) return 1; else return 0; } int main(){ int n; cin>>n; for(int i=1;i<=n;i++){ cin>>a[i].yw>>a[i].sx>>a[i].yy; a[i].sum=a[i].yw+a[i].sx+a[i].yy; a[i].id=i; } sort(a+1,a+n+1,cmp); for(int i=1;i<=5;i++){ cout<<a[i].id<<" "<<a[i].sum<<endl; } for(int i=1;i<=3;i++) break; return 0; }
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02024-11-23 18:42:51@
#include <stdio.h> #include <iostream> #include <bits/stdc++.h> using namespace std; struct student{ int num,yw,sx,yy,sum; string name; }a[10000]; int cmp(student a,student b) { if(a.sum>b.sum) { return 1; } else if(a.sumb.sum && a.yw>b.yw) { return 1; } else if(a.sumb.sum && a.yw==b.yw && a.num<b.num) { return 1; } else{ return 0; } } int main() { int n; cin>>n; for(int i=1;i<=n;i++) { cin>>a[i].yw>>a[i].sx>>a[i].yy; a[i].sum=a[i].yw+a[i].sx+a[i].yy; a[i].num=i;
} sort(a+1,a+n+1,cmp); for(int i=1;i<=5;i++) { cout <<a[i].num; cout << " "<<a[i].sum<<endl; }
}
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02024-11-3 14:14:59@
/* int %o/%lo 8 %d/%i/%ld/%li 10 %x/%lx 16 longlong %lld float %f/%e double %lf/%le char %c char[] %s 'a'=97 'z'=122 'A'=65 'Z'=90 '0'=48 '9'=57 */ #include <iostream> #include <iomanip> #include <cmath> #include <cstdio> #include <cstring> #include <algorithm> #include <ctime> #include <limits> #include <assert.h> #include <stdlib.h> using namespace std; #define LL long long #define ull unsigned long long const int N=1e5+10; const int INF=0x3f3f3f3f; const double pi=3.1416; int n; struct sb{ int c,m,e,t,id; }a[N]; bool cmp(sb a1,sb a2){ if(a1.t==a2.t){ if(a1.c==a2.c){ return a1.id<a2.id; } return a1.c>a2.c; } return a1.t>a2.t; } int main(){ cin>>n; for(int i=1;i<=n;i++){ cin>>a[i].c>>a[i].m>>a[i].e; a[i].t=a[i].c+a[i].m+a[i].e; a[i].id=i; } sort(a+1,a+n+1,cmp); for(int i=1;i<=5;i++){ cout<<a[i].id<<" "<<a[i].t<<endl; } return 0; }
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02024-3-17 20:27:49@
#include<bits/stdc++.h> using namespace std; const int N = 1e5 + 10; int n,k; struct stu { int id; int yw; int sx; int yy; int total; }a[N]; bool cmp(stu a1,stu a2) { if(a1.total == a2.total) { if(a1.yw == a2.yw) { a1.id < a2.id; } return a1.yw > a2.yw; } return a1.total > a2.total; } int main(){ cin >> n >> k; for(int i = 1;i <= n;i++) { cin >> a[i].id >> a[i].yw >> a[i].sx >> a[i].yy; a[i].total = a[i].yw + a[i].sx + a[i].yy; a[i].id = i; } sort(a + 1,a + n + 1,cmp); for (int i = 1;i <= 5;i++) cout << a[k].id << " " << a[k].yw; return 0; }
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02024-3-17 18:38:27@
简约代码
#include <iostream>//点个赞拿走 #include <algorithm> using namespace std; const int N = 1e5 + 10; int n,k; struct ikun{ int id , yu , shu , yin , to; }a[N]; bool cmp(ikun a1,ikun a2){//想抄P1363的同学 。 if (a1.to == a2.to)//记得删掉数学和英语。 { if (a1.yu == a2.yu) { return a1.id < a2.id; } return a1.yu > a2.yu; } return a1.to > a2.to; } int main(){ cin >> n; for (int i = 1;i <= n;i++) { cin >> a[i].yu >> a[i].shu >> a[i].yin; a[i].to = a[i].yu + a[i].shu + a[i].yin;//总和 a[i].id = i; } sort(a+1,a+n+1,cmp);//自定义排序。 for (int i = 1;i <= 5;i++) cout << a[i].id << " " << a[i].to << endl; }
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02023-8-19 17:23:03@
#include <iostream> #include <algorithm> using namespace std; int n; struct stu{ int chinese,maths,english; int tot,id; }; stu a[310]; bool cmp(stu A,stu B){ if(A.tot!=B.tot)return A.tot>B.tot; else if(A.chinese!=B.chinese)return A.chinese>B.chinese; else return A.id<B.id; } int main(){ cin>>n; for(int i=1;i<=n;i++){ cin>>a[i].chinese>>a[i].maths>>a[i].english; a[i].tot=a[i].chinese+a[i].maths+a[i].english; a[i].id=i; } sort(a+1,a+n+1,cmp); for(int i=1;i<=5;i++){ cout<<a[i].id<<" "<<a[i].tot<<endl; } }
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02023-6-3 8:19:09@
思路分析: 首先,读入n和每个学生的三门成绩,计算每个学生的总分,将学生信息存储在一个结构体数组中,然后按照总分、语文成绩、学号的顺序进行排序,最后输出前五名学生的学号和总分即可。
- 1
信息
- ID
- 691
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 5
- 标签
- 递交数
- 316
- 已通过
- 125
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