12 条题解

  • 2
    @ 2023-1-23 15:01:47
    #include<iostream>
    using namespace std;
    int main(){
    	int a,b;
    	cin>>a>>b;
    	cout<<a%b<<" "<<a/b;
    	return 0;
    }
    

    求赞

    • 1
      @ 2023-11-7 17:39:33
      #include <stack>
      #include <iostream>
      #include <iomanip>
      #include <string.h>
      #include <algorithm>
      using namespace std;
      int main() 
      {
          int n,m,a,b,c;
          cin>>n>>m;
          a=n/m;
          c=a*m;
          b=n-c;
          cout<<b<<" "<<a;
      }
      
      • 0
        @ 2024-9-27 18:45:57
        #include<bits/stdc++.h>
        const int N=1e5+10;
        using namespace std;
        int main(){
        	int a,b,c;//a表示跳绳数,b表示减去数
        	cin>>a>>c;
        	if(a%c==0){
        		cout<<a/c;
        	}
        	if(a%c!=0){
        		b=a%c;
        		a=a-b;
        		cout<<b<<" "<<a/c;
        	}
        	if(a==0&&b==0)
        		cout<<"0";
        	return 0;
        }
        
        
        
        
        
        
        
        
        
        然后,你错了😄 
        
        • 0
          @ 2024-3-30 17:28:34
          #include <iostream> 
          using namespace std;
          int main()
          {
          	int n,m,c,d;	
          	cin >>n>>m;
          	c = n % m;	
          	d = (n - c) / m;
          	cout << c << ' ' << d << endl;
          }
          
          • 0
            @ 2024-3-26 22:34:55

            #include <stdio.h> #include <iostream> using namespace std; int main() { int a,b cin>>a>>b cout<<a%b<<" "<<a/b;

            return 0;
            

            }

            • 0
              @ 2024-3-26 22:34:40

              #include <stdio.h> #include <iostream> using namespace std; int main() { int a,b; cin>>a>>b; cout<<a%b<<" "<<a/b;

              return 0;
              

              }

              • 0
                @ 2023-10-16 16:26:28

                #include<cstdio> #include<iostream> #include<cmath> #include<iomanip> using namespace std; int main(){ long long m,n; cin>>n>>m; cout<<n%m<<" "<<n/m; return 0; }

                • 0

                  #include <iostream> using namespace std; int main() { int a,b,c,d; cin>>a>>b; c=a%b; d=(a-c)/b; cout<<c<<" "<<d; }

                  • 0
                    @ 2022-11-14 17:55:20
                    #include <iostream>
                    using namespace std;int main(){int n,m,a,b,c;cin>>n>>m;a=n/m;c=a*m;b=n-c;cout<<b<<" "<<a;}
                    

                    哈哈哈哈哈哈

                    • 0
                      @ 2022-8-2 9:25:07

                      先用数学的方式理解

                      #include <stack>
                      #include <iostream>
                      #include <iomanip>
                      #include <string.h>
                      #include <algorithm>
                      using namespace std;
                      int main() 
                      {
                          int n,m,a,b,c;
                          cin>>n>>m;
                          a=n/m;
                          c=a*m;
                          b=n-c;
                          cout<<b<<" "<<a;
                      }
                      
                      
                    • -7
                      @ 2022-7-1 21:03:14

                      #include <stdio.h>

                      #include <iostream>

                      using namespace std;

                      int main()

                      {

                      int a,b;
                      
                      cin>> a >> b ;
                      
                      cout<< a % b << " " << (a - a % b) /b;
                      

                      }

                      • -12
                        @ 2022-1-8 10:54:52
                        #include <stack>
                        #include <iostream>
                        #include <iomanip>
                        #include <string.h>
                        #include <algorithm>
                        using namespace std;
                        
                        int main() {
                        int n,m,a,b,c;
                        cin>>n>>m;
                        a=n/m;
                        c=a*m;
                        b=n-c;
                        cout<<b<<" "<<a;
                        }
                        
                        • 1

                        信息

                        ID
                        811
                        时间
                        1000ms
                        内存
                        128MiB
                        难度
                        5
                        标签
                        递交数
                        1282
                        已通过
                        466
                        上传者