9 条题解
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1林晋宇 (ts2024stu010) LV 5 @ 2024-11-23 11:46:40
#include<bits/stdc++.h> using namespace std; int main() { double w,h,l,a; cin >> w; if(w == w) { h=2w; l=h3.14159; a=w*w * 3.14159; printf("%.4f %.4f %.4f",h,l,a); } }
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02024-11-23 11:47:50@
#include<bits/stdc++.h>
using namespace std;
int main()
{
double w,h,l,a;
cin >> w;
if(w == w)
{
h=2*w;
l=h*3.14159;
a=w*w * 3.14159;
printf("%.4f %.4f %.4f",h,l,a);
}
}
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02022-12-7 22:30:08@
#include<iostream> #include<iomanip> #include<math.h> using namespace std; int main(){ double r,d,c,s; cin>>r; d=r*2; c=d*3.14159; s=r*r*3.14159; cout<<fixed<<setprecision(4)<<d<<" "; cout<<fixed<<setprecision(4)<<c<<" "; cout<<fixed<<setprecision(4)<<s; }
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-12024-11-23 17:25:25@
#include<iostream> #include<iomanip> #include<cmath> using namespace std; int main() { double a,b,c,d; cin>>a; b=2.0a; c=2a3.14159; d=aa*3.14159; cout<<fixed<<setprecision(4)<<b<<" "; cout<<fixed<<setprecision(4)<<c<<" "; cout<<fixed<<setprecision(4)<<d; return 0; } 挺简单的
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-12024-11-22 20:15:28@
#include<iostream> #include<iomanip> #include<cmath> using namespace std; int main() { double n,z,c,s; cin>>n; z=2.0n; c=2n3.14159; s=nn*3.14159; cout<<fixed<<setprecision(4)<<z<<" "; cout<<fixed<<setprecision(4)<<c<<" "; cout<<fixed<<setprecision(4)<<s;
return 0;
}
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-12024-11-22 18:06:04@
#include<bits/stdc++.h> using namespace std; int main(){ double r; cin>>r; double d,c,s; d=2r; c=23.14159r; s=3.14159pow(r,2); printf("%.4lf %.4lf %.4lf",d,c,s); return 0; }
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-12024-4-6 19:37:42@
#include<iostream> #include<iomanip> #include<math.h> using namespace std; int main(){ double r,d,c,s; cin>>r; d=r2; c=d3.14159; s=rr3.14159; cout<<fixed<<setprecision(4)<<d<<" "; cout<<fixed<<setprecision(4)<<c<<" "; cout<<fixed<<setprecision(4)<<s; }
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-12022-2-13 19:50:37@
#include<bits/stdc++.h> using namespace std; int main() { double r,zhi,z,c; cin >> r; if(r == r) { zhi=2*r; z=zhi*3.14159; c=r*r * 3.14159; printf("%.4f %.4f %.4f",zhi,z,c); } }
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-22022-7-2 20:43:05@
#include<stdio.h> #include<iostream> using namespace std; int main() { double a,b,c,d,pi; cin>>a; pi=3.14159; b=a2; printf("%.4lf ",b); c=pib; printf("%.4lf ",c); d=piaa; printf("%.4lf ",d); }
- 1
信息
- ID
- 889
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 3
- 标签
- 递交数
- 329
- 已通过
- 187
- 上传者