8 条题解

  • 1

    之前只拿了80分的屑今天再次挑战!

    AC成功好吧

    #include <bits/stdc++.h>
    using namespace std;
    const int N=1e6+10;
    const int INF=0x3f3f3f3f;
    int n,song[N],d,sum,ans;
    int main()
    {
    	cin>>d>>n;
    	for(int i=1;i<=n;i++)
    	{
    		cin>>song[i];
    		sum+=song[i];
    	}
    	ans+=(d/sum)*n;
    	d=d%sum;
    	int i=1;
    	while(d>0)
    	{
    		d-=song[i];
    		ans++;
    		i++;
    		if(i>n)
    		{
    			i=1;
    		}
    	} 
    	cout<<ans;
    	return 0;
    }
    
    
  • 1
    @ 2023-3-31 19:27:30
    #include<iostream>
    #include<math.h>
    using namespace std;
    int d,n,s[10001],sum,cs;
    int main(){
    	cin>>d>>n;
    	for(int i=1;i<=n;i++){
    		cin>>s[i];
    		sum+=s[i];
    	}
    	cs=d/sum;d-=cs*sum;cs*=n;
    	int i=1;
    	while(0<d){
    		d-=s[i];
    		cs++;i++;
    	}
    	cout<<cs;
    	return 0;
    }
    
    • 0
      @ 2024-5-26 9:40:14

      也是拿AC了好吧

      using namespace std;
      int main(){
      	int D,N,sum=0,j=1,cnt=0;
      	cin>>D>>N;
      	int a[1000005];
      	for(int i=1;i<=N;i++){
      		cin>>a[i];
      		sum+=a[i];
      	}
      	cnt=D/sum*N;
      	D=D%sum;
      	while(D>0){
      		D=D-a[j];
      		cnt++;
      		j++;
      	}
      	cout<<cnt;
      	return 0;
      }
      
      • 0
        @ 2024-5-26 9:40:13
        #include<bits/stdc++.h>
        using namespace std;
        int main()
        {
        	long long x,c,z=0,m=0,u=0,i;
        	cin>>x>>c;
        	int a[c+1]={0};
        	for(i=0;i<c;i++)cin>>a[i],m+=a[i];
        	z=x%m;
        	u=x/m;
        	for(i=0;z>0;i++)z-=a[i];
        	cout<<u*c+i;
        	return 0;
        }
        
        • 0
          @ 2024-5-26 9:39:01
          #include
          using namespace std;
          int main(){
          	int D,N,sum=0,j=1,cnt=0;
          	cin>>D>>N;
          	int a[1000005];
          	for(int i=1;i<=N;i++){
          		cin>>a[i];
          		sum+=a[i];
          	}
          	cnt=D/sum*N;
          	D=D%sum;
          	while(D>0){
          		D=D-a[j];
          		cnt++;
          		j++;
          	}
          	cout<<cnt;
          	return 0;
          }
          
          • 0
            @ 2023-12-8 19:29:14
            #include <iostream>
            using namespace std;
            int d, n, sum, t, s, num;
            int a[1000005];
            int main()
            {
            	scanf("%d%d", &d, &n);
            	for(int i = 0;i < n;i++)
            	{
            		scanf("%d", &a[i]);
            		sum += a[i];
            	}
            	s = d / sum * n;//整数组
            	d %= sum;//余数 
            	//只需要计算小于n个的余数即可 
            	while(num < d)
            	{
            		num += a[t % n];
            		t++;
            //		cout << t << " " << t % n << " " << a[t % n] << " " << sum<< endl;
            	}
            	printf("%d\n", t + s);
            	return 0; 
            }
            
            • 0

              自己做的代码也是成功AC好吧

              #include<bits/stdc++.h>
              using namespace std;
              int main()
              {
              	long long x,c,z=0,m=0,u=0,i;
              	cin>>x>>c;
              	int a[c+1]={0};
              	for(i=0;i<c;i++)cin>>a[i],m+=a[i];
              	z=x%m;
              	u=x/m;
              	for(i=0;z>0;i++)z-=a[i];
              	cout<<u*c+i;
              	return 0;
              }
              
              • 0
                @ 2022-7-9 20:59:18
                /*****************************************
                备注:
                ******************************************/
                #include <queue>
                #include <math.h>
                #include <stack>
                #include <stdio.h>
                #include <iostream>
                #include <vector>
                #include <iomanip>
                #include <string.h>
                #include <algorithm>
                using namespace std;
                #define LL long long
                const int N = 1e6 + 10;
                const int INF = 0x3f3f3f3f;
                int n ,a[N];
                int main()
                {
                	int n,s ;
                	cin >>s >> n ;
                	int ans = 0;
                	for(int i =1 ;i <= n ;i++)
                	{
                		cin >> a[i];
                		ans += a[i];
                	}
                	int len = 1;
                	int sum = s/ans *n;
                	s %= ans;
                	while(s > 0)
                	{
                		sum++;
                		s -= a[len];
                		len++;
                		if(len > n)
                			len= 1;
                	}
                	cout << sum << endl;
                	return 0;
                }
                
                • 1

                信息

                ID
                993
                时间
                1000ms
                内存
                128MiB
                难度
                7
                标签
                递交数
                443
                已通过
                108
                上传者