#include #include <math.h> #include #include <stdio.h> #include #include #include #include <string.h> #include using namespace std; #define LL long long const int N = 1e5 + 10; const int INF = 0x3f3f3f3f; int a[N]; int main() { int d, n; cin>> d >> n; int num = 0 ; for(int i = 1 ; i <= n ; i++) { cin>> a[i]; num += a[i]; } int id = 1 , sum = 0; sum = (d / num) * n; d = d % num; while(d> 0) { d -= a[id]; id++; if(id == n+1) id = 1; sum++; } cout << sum << endl; return 0; }

也是拿AC了好吧

using namespace std;
int main(){
	int D,N,sum=0,j=1,cnt=0;
	cin>>D>>N;
	int a[1000005];
	for(int i=1;i<=N;i++){
		cin>>a[i];
		sum+=a[i];
	}
	cnt=D/sum*N;
	D=D%sum;
	while(D>0){
		D=D-a[j];
		cnt++;
		j++;
	}
	cout<<cnt;
	return 0;
}

#include<bits/stdc++.h>
using namespace std;
int main()
{
	long long x,c,z=0,m=0,u=0,i;
	cin>>x>>c;
	int a[c+1]={0};
	for(i=0;i<c;i++)cin>>a[i],m+=a[i];
	z=x%m;
	u=x/m;
	for(i=0;z>0;i++)z-=a[i];
	cout<<u*c+i;
	return 0;
}

#include
using namespace std;
int main(){
	int D,N,sum=0,j=1,cnt=0;
	cin>>D>>N;
	int a[1000005];
	for(int i=1;i<=N;i++){
		cin>>a[i];
		sum+=a[i];
	}
	cnt=D/sum*N;
	D=D%sum;
	while(D>0){
		D=D-a[j];
		cnt++;
		j++;
	}
	cout<<cnt;
	return 0;
}

#include <iostream>
using namespace std;
int d, n, sum, t, s, num;
int a[1000005];
int main()
{
	scanf("%d%d", &d, &n);
	for(int i = 0;i < n;i++)
	{
		scanf("%d", &a[i]);
		sum += a[i];
	}
	s = d / sum * n;//整数组
	d %= sum;//余数 
	//只需要计算小于n个的余数即可 
	while(num < d)
	{
		num += a[t % n];
		t++;
//		cout << t << " " << t % n << " " << a[t % n] << " " << sum<< endl;
	}
	printf("%d\n", t + s);
	return 0; 
}

自己做的代码也是成功AC好吧

#include<bits/stdc++.h>
using namespace std;
int main()
{
	long long x,c,z=0,m=0,u=0,i;
	cin>>x>>c;
	int a[c+1]={0};
	for(i=0;i<c;i++)cin>>a[i],m+=a[i];
	z=x%m;
	u=x/m;
	for(i=0;z>0;i++)z-=a[i];
	cout<<u*c+i;
	return 0;
}

之前只拿了80分的屑今天再次挑战！

AC成功好吧

#include <bits/stdc++.h>
using namespace std;
const int N=1e6+10;
const int INF=0x3f3f3f3f;
int n,song[N],d,sum,ans;
int main()
{
	cin>>d>>n;
	for(int i=1;i<=n;i++)
	{
		cin>>song[i];
		sum+=song[i];
	}
	ans+=(d/sum)*n;
	d=d%sum;
	int i=1;
	while(d>0)
	{
		d-=song[i];
		ans++;
		i++;
		if(i>n)
		{
			i=1;
		}
	} 
	cout<<ans;
	return 0;
}

#include<iostream>
#include<math.h>
using namespace std;
int d,n,s[10001],sum,cs;
int main(){
	cin>>d>>n;
	for(int i=1;i<=n;i++){
		cin>>s[i];
		sum+=s[i];
	}
	cs=d/sum;d-=cs*sum;cs*=n;
	int i=1;
	while(0<d){
		d-=s[i];
		cs++;i++;
	}
	cout<<cs;
	return 0;
}

/*****************************************
备注：
******************************************/
#include <queue>
#include <math.h>
#include <stack>
#include <stdio.h>
#include <iostream>
#include <vector>
#include <iomanip>
#include <string.h>
#include <algorithm>
using namespace std;
#define LL long long
const int N = 1e6 + 10;
const int INF = 0x3f3f3f3f;
int n ,a[N];
int main()
{
	int n,s ;
	cin >>s >> n ;
	int ans = 0;
	for(int i =1 ;i <= n ;i++)
	{
		cin >> a[i];
		ans += a[i];
	}
	int len = 1;
	int sum = s/ans *n;
	s %= ans;
	while(s > 0)
	{
		sum++;
		s -= a[len];
		len++;
		if(len > n)
			len= 1;
	}
	cout << sum << endl;
	return 0;
}

#include #include <math.h> #include #include <stdio.h> #include #include #include #include <string.h> #include using namespace std; #define LL long long const int N = 1e6 + 10; const int INF = 0x3f3f3f3f; int n ,a[N]; int main() { int n,s ; cin >>s >> n ; int ans = 0; for(int i =1 ;i <= n ;i++) { cin >> a[i]; ans += a[i]; } int len = 1; int sum = s/ans *n; s %= ans; while(s > 0) { sum++; s -= a[len]; len++; if(len > n) len= 1; } cout << sum << endl; return 0; } //我是大聪明，哈哈！