18 条题解

  • 1
    @ 2024-5-3 12:29:31

    #include using namespace std; int main(){ int n; cin>>n; if(n%30&&n%50) { cout<<"YES"; } else{ cout<<"NO" ; } return 0; }

    • 1
      @ 2024-4-12 21:52:50
      #include <queue>
      #include <math.h>
      #include <stack>
      #include <stdio.h>
      #include <iostream>
      #include <vector>
      #include <iomanip>
      #include <string.h>
      #include <algorithm>
      #include <bits/stdc++.h>
      using namespace std;
      const int N = 1e6 + 10;
      const int INF = 0x3f3f3f3f;
      int main()
      {
      	int a;
      	cin >> a;
      	if( a % 3 == 0 && a % 5 == 0 )
      	{
      		cout << "YES";
      	}
      	else
      	{
      		cout << "NO";
      	}
      	return 0;
      }
      
      • 0
        @ 2025-7-9 11:23:49

        #include

        using namespace std;

        int main()

        {

        int a;
        cin >> a;
        if( a % 3 == 0 && a % 5 == 0 )
        {
        cout << "YES";
        }
        else
        {
        cout << "NO";
        }
        return 0;
        

        }

        • 0
          @ 2024-12-11 14:00:33
          n = int(input())
          if n % 15 == 0:
              print("YES")
          else:
              print("NO")
          
          • 0
            @ 2024-5-29 20:25:28
            col1 col2 col3
            #include
            using namespace std;
            int main()
            {
            int a,b,c;
            cin>>a>>b>>c;
            if(a+b>c){if (c+b>a){if(a+c>b){cout<<"yes";
            }else{cout<<"no";}
            return 0;
            }
            • 0
              @ 2024-5-29 20:24:22

              #include using namespace std; int main() { int n; cin>>n; if(n%30&&n%50) { cout<<"YES"; } else{ cout<<"NO" ; } return 0; }

              • 0
                @ 2023-8-12 11:33:24
                #include <iostream>
                #include <stdio.h>
                #include <iomanip>
                #include <math.h>
                using namespace std;
                const int N = 1e6 + 10;
                const int INF = 0x3f3f3f3f;
                int main()
                {
                	int a;
                	cin >> a;
                	if( a % 3 == 0 && a % 5 == 0 )
                	{
                		cout << "YES";
                	}
                	else
                	{
                		cout << "NO";
                	}
                	return 0;
                }
                
                • 0
                  @ 2023-5-11 18:05:45

                  #include

                  using namespace std;

                  int main()

                  {

                  int a;

                  cin>>a;

                  if(a%30&&a%50)

                  {

                  cout<<"YES";

                  }

                  else

                  { cout<<"NO";

                  }

                  return 0;

                  }

                  • 0
                    @ 2022-12-10 18:26:55

                    可恶再度把添胜第3周没做完的愤怒发泄在题解上(?

                    最小公倍数指一个数能同时除以两个或以上的数,并且这个数是最小的,那这个数就是这些数 的最小公倍数。(不懂的话看五年级下册数学书去吧

                    这一题,能同时整除3和5的数也一定能整除3和5的最小公倍数15(15既能整除3又能整除5,而且15以内的正整数都不能同时整除3和5

                    上代码:

                    #include<bits/stdc++.h>
                    using namespace std;
                    
                    int main(){
                    	int n;
                    	cin>>n;
                    	if(n%15==0)cout<<"YES";
                    	else cout<<"NO";
                    	return 0;
                    }
                    

                    因为懒所以不加注释了,,

                    欢迎来luogu找我玩!

                    • 0
                      @ 2022-12-9 13:51:04

                      #include using namespace std; int main(){ int a; cin>>a; if(a%30&&a%50){ cout<<"YES"; }else{ cout<<"NO"; } }

                      • 0
                        @ 2022-12-4 16:42:33
                        • #include <stdio.h>
                          #include <iostream>
                          #include <math.h>
                          #include <iomanip>
                          using namespace std;
                          int main()
                          {
                          	int n;
                          	cin>>n;
                          	if(n % 3 == 0 && n % 5 == 0)
                          	{
                          		cout<<"YES";
                          	}
                          	else
                          	{
                          		cout<<"NO";
                          	}
                          }
                          

                          Copy *

                        • 0
                          @ 2022-1-3 9:29:47
                          #include <stdio.h>
                          #include <iostream>
                          #include <math.h>
                          #include <iomanip>
                          using namespace std;
                          int main()
                          {
                          	int n;
                          	cin>>n;
                          	if(n % 3 == 0 && n % 5 == 0)
                          	{
                          		cout<<"YES";
                          	}
                          	else
                          	{
                          		cout<<"NO";
                          	}
                          }
                          
                          • -1
                            @ 2023-4-4 21:38:33

                            #include<bits/stdc++.h> using namespace std; int main() { int n; cin>>n; if(n%30&&n%50) cout<<"YES"; else cout<<"NO"; return 0; }

                            • -1
                              @ 2023-1-12 11:48:07

                              #include #include using namespace std; int main(){ int a; cin>>a; if (a%30 and a%50){ cout<<"YES"; } else{ cout<<"NO"; } }

                              • -2
                                @ 2022-3-30 20:36:09

                                #include

                                using namespace std;

                                int main(){

                                int a;
                                
                                cin>>a;
                                
                                if(a%15==0){
                                
                                	cout<<"YES";
                                
                                }else{
                                
                                	cout<<"NO";
                                
                                }
                                

                                } //极简主义

                                • -4
                                  @ 2022-7-2 18:38:25

                                  #include #include<stdio.h> using namespace std; int main() { long long a; cin>>a; if(a%30&&a%50) { cout<<"YES"<<endl; }else { cout<<"NO"<<endl; } }

                                  • -5
                                    @ 2022-1-3 9:23:50
                                    #include <stdio.h>
                                    #include <iostream>
                                    #include <math.h>
                                    #include <iomanip>
                                    using namespace std;
                                    int main()
                                    {
                                    	int n;
                                    	cin>>n;
                                    	if(n%3==0&&n%5==0)
                                    	{
                                    		cout<<"YES";
                                    	}
                                    	else
                                    	{
                                    		cout<<"NO";
                                    	}
                                    }
                                    ``
                                    • -6
                                      @ 2021-10-20 13:44:31

                                      n = int(input()) if n % 3 == 0 and n % 5 == 0 and n != 0: print("YES") if n % 3 != 0 or n % 5 != 0 or n % 3 != 0 and n % 5 == 0 or n % 3 == 0 and n % 5 != 0 or n == 0: print("NO")

                                      • 1

                                      判断一个数能否同时被3和5整除

                                      信息

                                      ID
                                      870
                                      时间
                                      1000ms
                                      内存
                                      128MiB
                                      难度
                                      4
                                      标签
                                      递交数
                                      792
                                      已通过
                                      386
                                      上传者