11 条题解

  • 1
    @ 2023-3-11 21:23:41
    #include<iostream>
    #include<iomanip>
    using namespace std;
    int main()
    {
        int n,tmp,a1=0,a2=0,a3=0,a4=0;
        cin>>n;
        for(int i=0;i<n;i++)
        {
            cin>>tmp;
            if(tmp<=18)a1+=1;
            else if(19<=tmp&&tmp<=35)a2+=1;
            else if(36<=tmp&&tmp<=60)a3+=1;
            else if(tmp>=61)a4+=1;
        }
        cout<<fixed<<setprecision(2);
        cout<<a1*100.0/n<<'%'<<endl;
        cout<<a2*100.0/n<<'%'<<endl;
        cout<<a3*100.0/n<<'%'<<endl;
        cout<<a4*100.0/n<<'%'<<endl;
        return 0;
    }
    
    
    • 0
      @ 2026-4-12 19:23:44

      #include #include using namespace std; int main() { int n,tmp,a1=0,a2=0,a3=0,a4=0; cin>>n; for(int i=0;i<n;i++) { cin>>tmp; if(tmp<=18)a1+=1; else if(19<=tmp&&tmp<=35)a2+=1; else if(36<=tmp&&tmp<=60)a3+=1; else if(tmp>=61)a4+=1; } cout<<fixed<<setprecision(2); cout<<a1100.0/n<<'%'<<endl; cout<<a2100.0/n<<'%'<<endl; cout<<a3100.0/n<<'%'<<endl; cout<<a4100.0/n<<'%'<<endl; return 0; }

      • 0
        @ 2025-11-15 17:18:17

        #include <bits/stdc++.h> #define maxn 300000 using namespace std; typedef long long ll; int n,a[maxn],h1,h2,h3,h4; double l; int main(){ cin>>n; for(int i=1;i<=n;i++){ cin>>a[i]; if(a[i]<=18) h1++; else if(a[i]<=35) h2++; else if(a[i]<=60) h3++; else h4++; } printf("%.2lf%\n%.2lf%\n%.2lf%\n%.2lf%",h1100.0/n,h2100.0/n,h3100.0/n,h4100.0/n); }</u>**********

        • 0
          @ 2025-11-7 20:57:06
          #include <bits/stdc++.h>
          using namespace std;
          int sum[4];
          int main(){
              int n;
              cin>>n;
              int age;   
              for(int i=1;i<=n;i++){
                  cin>>age;
                  if(age<=18) 
                      sum[0]++;
                  else if(age<=35)
                      sum[1]++;
                  else if(age<=60)
                      sum[2]++;
                  else
                      sum[3]++;
              }
              
              cout<<fixed<<setprecision(2);
              for(int i=0;i<4;i++)
                  cout<<sum[i]*100.0/n<<"%"<<endl;  
              return 0;
          }
          • 0
            @ 2024-10-11 22:42:10

            #include <stdio.h> #include #include <math.h> #include #include<bits/stdc++.h> using namespace std; int main() { int a,b[100]; float c=0,d=0,e=0,f=0; cin>>a; for(int i=1;i<=a;i++){ cin>>b[i]; } for(int i=1;i<=a;i++){ if(0<=b[i]&&b[i]<=18){ c++; }else{ if(b[i]<=35){ d++; }else{ if(b[i]<=60){ e++; }else{ f++; } } } } c=c/a; d=d/a; e=e/a; f=f/a; cout<<fixed<<setprecision(2)<<c100; cout<<"%"<<endl; cout<<fixed<<setprecision(2)<<d100; cout<<"%"<<endl; cout<<fixed<<setprecision(2)<<e100; cout<<"%"<<endl; cout<<fixed<<setprecision(2)<<f100; cout<<"%"; return 0; }

            • 0
              @ 2024-6-11 21:00:45

              #include #include using namespace std; int main() { double n,tmp,a1=0,a2=0,a3=0,a4=0; cin>>n; for(int i=0;i<n;i++) { cin>>tmp; if(tmp<=18)a1+=1; else if(19<=tmp&&tmp<=35)a2+=1; else if(36<=tmp&&tmp<=60)a3+=1; else if(tmp>=61)a4+=1; } cout<<fixed<<setprecision(2); cout<<a1100.0/n<<'%'<<endl; cout<<a2100.0/n<<'%'<<endl; cout<<a3100.0/n<<'%'<<endl; cout<<a4100.0/n<<'%'<<endl; }

              • 0
                @ 2024-5-18 15:57:07
                #include <bits/stdc++.h>
                #define maxn 300000
                using namespace std;
                typedef long long ll;
                int n,a[maxn],h1,h2,h3,h4;
                double l;
                int main(){
                	cin>>n;
                	for(int i=1;i<=n;i++){
                		cin>>a[i];
                		if(a[i]<=18) h1++;
                		else if(a[i]<=35) h2++;
                		else if(a[i]<=60) h3++;
                		else h4++;
                	}
                	printf("%.2lf\%\n%.2lf\%\n%.2lf\%\n%.2lf\%",h1*100.0/n,h2*100.0/n,h3*100.0/n,h4*100.0/n);
                }
                
                • 0
                  @ 2023-9-10 11:39:42
                  #include <bits/stdc++.h>
                  using namespace std;
                  const int N=1e7+10;
                  const int INF=0x3f3f3f3f;
                  int a[N],n,z1,z2,z3,z4; 
                  int main()
                  {
                  	cin>>n;
                  	for(int i=1;i<=n;i++)
                  	{
                  		cin>>a[i];
                  		if(a[i]>=0 && a[i]<=18)
                  		{
                  			z1++;
                  		}
                  		else if(a[i]>=19 && a[i]<=35)
                  		{
                  			z2++;
                  		}
                  		else if(a[i]>=36 && a[i]<=60)
                  		{
                  			z3++;
                  		}
                  		else if(a[i]>=61)
                  		{
                  			z4++;
                  		}
                  	}
                  	cout<<fixed<<setprecision(2)<<z1*100.0/n<<"%\n";
                  	cout<<fixed<<setprecision(2)<<z2*100.0/n<<"%\n";
                  	cout<<fixed<<setprecision(2)<<z3*100.0/n<<"%\n";
                  	cout<<fixed<<setprecision(2)<<z4*100.0/n<<"%\n";
                  	return 0;
                  }
                  
                  • 0
                    @ 2023-4-4 22:26:48
                    #include<iostream>
                    using namespace std;
                    int n,a,b,c,d;
                    void out(int x){
                    	printf("%.2lf",100.0*x/n);
                    	cout<<"%\n";
                    }
                    int main(){
                    	int x;
                    	cin>>n;
                    	for(int i=1;i<=n;i++){
                    		cin>>x;
                    		if(0<=x&&x<=18)a++;
                    		else if(x<=35)b++;
                    		else if(x<=60)c++;
                    		else d++;
                    	}
                    	out(a);out(b);out(c);out(d);
                    	return 0;
                    }
                    
                    • 0
                      @ 2023-2-19 15:00:51

                      #include <bits/stdc++.h>

                      using namespace std;

                      int a[1005];

                      int main(){

                      int n,x,ans1 = 0,ans2 = 0,ans3 = 0,ans4 = 0;

                      cin>>n;

                      for(int i =1;i<=n;i++){

                      cin>>x;

                      if(0 <= x && x <= 18) ans1++;

                      else if(x<=35) ans2++;

                      else if(x<=60) ans3++;

                      else ans4++;

                      }

                      cout<<fixed<<setprecision(2);

                      cout<<1.0ans1 / n100<<"%"<<endl;

                      cout<<1.0ans2 / n100<<"%"<<endl;

                      cout<<1.0ans3 / n100<<"%"<<endl;

                      cout<<1.0ans4 / n100<<"%"<<endl;

                      }

                      • 0
                        @ 2022-8-12 20:43:30
                        #include <bits/stdc++.h>
                        
                        using namespace std;
                        
                        //0-18、19-35、36-60、more than 61
                        
                        int p_q[101];
                        
                        int main(void)
                        {
                        	int n;
                        	
                        	cin >> n;
                        	
                        	float q0, q19, q36, q61;
                        	
                        	
                        	for (int i = 0; i <= n - 1; i++)
                        	{
                        		cin >> p_q[i];
                        	}
                        	
                        	for (int i = 0; i <= n - 1; i++)
                        	{
                        		if (p_q[i] <= 18 && p_q >= 0)
                        		{
                        			q0++;
                        		}
                        		
                        		if (p_q[i] <= 35 && p_q[i] >= 19)
                        		{
                        			q19++;
                        		}
                        		
                        		if (p_q[i] <= 60 && p_q[i] >= 36)
                        		{
                        			q36++;
                        		}
                        		
                        		if (p_q[i] >= 61)
                        		{
                        			q61++;
                        		}
                        	}
                        	
                        	printf("%0.2f%\n", q0 / n * 100);
                        	printf("%0.2f%\n", q19 / n * 100);
                        	printf("%0.2f%\n", q36 / n * 100);
                        	printf("%0.2f%%", q61 / n * 100);
                        	
                        	return 0;
                        }
                        
                        • 1

                        信息

                        ID
                        1006
                        时间
                        1000ms
                        内存
                        128MiB
                        难度
                        5
                        标签
                        递交数
                        628
                        已通过
                        240
                        上传者